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3 years ago

5000-5000×0+500+600-1100+10+10-20=

Mathematics

1 answer:

djverab [1.8K]3 years ago

3 0

Answer:

5000-5000×0+500+600-1100+10+10-20=5000

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What is 60% of 300?

V125BC [204]

Do a proportion
60/100= x/300
60 x 300= 18,000
18,000 divided by 100= 180
Answer is 180

Or you could have done .60 x 300 and got 180.

3 0

3 years ago

Read 2 more answers

Rico wants to find the distance between the points (-2,-3) and (2,-5) his work is shown.|-3| + |-5| = 3+5 = 8the distance is 8 u

tino4ka555 [31]

Answer:

Riko is wrong

Step-by-step explanation:

To find the distance of two point, we use the following formula:

A (x1, y1)

B (x1, y2)

AB = $\sqrt{(x2-x1)^{2} + (y2-y1)^{2} }$

In this situation, we have:

A (-2,-3)

B (2,-5)

So the distance is: $\sqrt{(2 - (-2))^{2} + (-5 - (-3))^{2} }$ = $\sqrt{4^{2} + 8^{2} }$ = $\sqrt{80} = 4\sqrt{5}$

Hope it will find you well.

5 0

3 years ago

Read 2 more answers

In a small private school, five students are randomly selected from eighteen available students. What is the probability that t

guajiro [1.7K]

Answer:

1 / 8568

Step-by-step explanation:

The number of combinations is:

₁₈C₅ = (18! / (5! (18−5)!)

₁₈C₅ = 8568

There are 8568 possible groups of 5 that can be selected from 18. Only 1 of those groups contains the five youngest students. So the probability is:

P = 1 / 8568 ≈ 0.0117%

4 0

4 years ago

What are the solutions of the equation x4 - 9x2 + 8 = 0? Use u substitution to solve.

Sedbober [7]

Answer:

$\large\boxed{B.\ x=\pm1\ and\ x=\pm2\sqrt2}$

Step-by-step explanation:

$x^4-9x^2+8=0\\\\x^{2\cdot2}-9x^2+8=0\qquad\text{use}\ (a^n)^m=a^{nm}\\\\(x^2)^2-9x^2+8=0\\\\\text{substitute}\ x^2=t\geq0\\\\t^2-9t+8=0\\\\t^2-t-8t+8=0\\\\t(t-1)-8(t-1)=0\\\\(t-1)(t-8)+0\iff t-1=0\ \vee\ t-8=0\\\\t-1=0\qquad\text{add 1 to both sides}\\t=1\geq0\\\\t-8=0\qquad\text{add 8 to both sides}\\t=8\geq0$

$t=x^2\to x^2=1\ \vee\ x^2=8\\\\x^2=1\Rightarrow x=\pm\sqrt1\to x=\pm1\\\\x^2=8\Rightarrow x=\pm\sqrt8\to x=\pm\sqrt{4\cdot2}\to x=\pm\sqrt4\cdot\sqrt2\to x=\pm2\sqrt2$