3 years ago

5000-5000×0+500+600-1100+10+10-20=

Mathematics

1 answer:

djverab [1.8K]3 years ago

3 0

Answer:

5000-5000×0+500+600-1100+10+10-20=5000

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Cone a and cone b both have a height of 5 in. The volume of cone a is 20.9cubic in, the volume of cone b is 4 times the volume o

Greeley [361]

Answer: two times

Step-by-step explanation:

Given

height of cone A and B $h_a=h_b=5\ in.$

The volume of cone A $V_a=20.9\ in.^3$

The volume of cone B is 4 times of cone A

the volume of a cone is $\frac{1}{3}\pi r^2h$

The volume of cone A

$V_a=\dfrac{1}{3}\pi r_a^2h_a=20.9\quad \ldots(i)$

The volume of cone B

$V_b=\dfrac{1}{3}\pi r_b^2h_b=4\times 20.9\quad \ldots(ii)$

divide (i) and (ii) we get

$\Rightarrow \dfrac{r_a^2}{r_b^2}=\dfrac{1}{4}\\\Rightarrow \dfrac{r_a}{r_b}=\sqrt{\dfrac{1}{4}}=\dfrac{1}{2}\\\Rightarrow \dfrac{d_a}{d_b}=\dfrac{1}{2}\\\Rightarrow d_b=2d_a$

thus, diameter of cone B is twice the diameter of A

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All 3000 seats in a theater are being replaced. So far, 5 section of 236 seats and a sixth section containing 348 seats have bee

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So, to find the number of seats already replaced:

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So 1528 seats have been replaced.

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And 1472 seats still need to be replaced.

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