Question

The length of a rectangle 4 yd is longer than its width. If the perimeter of the rectangle is 68 yd, find its length and width.

Answer 1

w + 4

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l l

l l w

l l

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Perimeter would be the sum of all the sides so: (w+4) + w + (w+4) + w

Perimeter is 60 yards according to your problem so: (w+4) + w + (w+4) + w = 60 yds

1.Simplify/combine like terms:

w + 4 + w + w + 4 + w =

4w + 8 =

Now it's a 2-step algebra equation

4w + 8 = 60

2.Subtract 8 on both sides

4w = 56

3.Divide both sides by 4

w = 14