Answer:
By comparing the ratios of sides in similar triangles ΔABC and ΔADB,we can say that 
Step-by-step explanation:
Given that ∠ABC=∠ADC, AD=p and DC=q.
Let us take compare Δ ABC and Δ ADB in the attached file , ∠A is common in both triangles
and given ∠ABC=∠ADB=90°
Hence using AA postulate, ΔABC ≈ ΔADB.
Now we will equate respective side ratios in both triangles.
Since we don't know BD , BC let us take first equality and plugin the variables given in respective sides.
Cross multiply
Hence proved.
3:1 =300%
2:3:5 =50%
1:4 =25%
1:2:5 =62.5%
Answer:
26.88 mm
Step-by-step explanation:
4.2 x 12.8 = 53.76/2 = 26.88
Answer:
Therefore, the conclusion is valid.
The required diagram is shown below:
Step-by-step explanation:
Consider the provided statement.
Premises: All good students are good readers. Some math students are good students.
Conclusion: Some math students are good readers.
It is given that All good students are good readers, that means all good students are the subset of good readers.
Now, it is given that some math students are good students, that means there exist some math student who are good students as well as good reader.
Therefore, the conclusion is valid.
The required diagram is shown below:
Answer:
27x +42+ 3x²
Step-by-step explanation:
so im learning this rn in class and what you do is FOIL
So its stands for
First
Outside
Inside
Last
(3x+6)(x+7)
(3x+6)(x+7) -- 3x² (if you have x times x it is x to the second power)
(3x+6)(x+7) -- 21x
(3x+6)(x+7) -- 6x
(3x+6)(x+7) -- 42
Now add 21x and 6x
27x +42+ 3x²
you must have added the 21 and 6 incorrectly.
