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2 years ago

The diameter of a circle measures 20 yd. What is the circumference of the circle?

Mathematics

1 answer:

Pani-rosa [81]2 years ago

5 0

Answer: 62.8 yd

Step-by-step explanation:

Circumference= diameter*pi

20*3.14= 62.8

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Solve. You must factor first. 8n^2 29n + 15 = 0 Please show work

lord [1]

Answer: Multiply n299 by n by adding the exponents

Step-by-step explanation:

8n230+15=0

8 0

3 years ago

Can someone help me understand this?

choli [55]

Get the equation to slope-intercept form: y = mx + b

6x + 3y = 6

Subtract 6x from both sides. This will give you 3y = -6x + 6.

Then, divide by 3 on both sides. This gives you y = -6x + 2.

2 is your y intercept and -6 is your slope.

3 0

3 years ago

Read 2 more answers

HELP PLEASE URGENTTT!!!!!

Nina [5.8K]

Answer:

I believe the answer is x = 3

8 0

3 years ago

What 2 numbers multiply to be 108 but subtract to be 6

mel-nik [20]

No 2 numbers do this.

Possible numbers that can multiply to 108:

1 x 108 = 108
2 x 54 = 108
3 x 36 = 108
4 x 27 = 108
6 x 18 = 108
9 x 12 = 108
12 x 9 = 108
18 x 6 = 108
27 x 4 = 108
36 x 3 = 108
54 x 2 = 108
108 x 1 = 108

Possible numbers on that list that when subtracted equate to 6:

None

3 0

2 years ago

In a jury trial, suppose the probability the defendant is convicted, given guilt, is 0.95, and the probability the defendant is

Artyom0805 [142]

Answer:

The probability of the defendant is innocent given the defendant is convicted is P=0.006.

Step-by-step explanation:

Being:

G: guilty, I:innocent, C: convicted, A: acquitted.

We need to calculate P(I|C).

Being innocent, given convicted, is equal to the probability of being innocent and convicted divided by the probability of being convicted (innocent or guilty)

$P(I|C)=\frac{P(I\&C)}{P(C)}$

The probability of being innocent and convicted is

$P(I\&C)=P(C|I)*P(I)=0.05*0.1=0.005$

The probability of being convicted is equal to the sum of P(I&C) and P(G&C)

$P(C)=P(I\&C)+P(I\&C)=P(C|I)*P(I)+P(C|G)*P(G)\\\\P(C)=0.005+0.95*0.90=0.005+0.855=0.86$

Then,

$P(I|C)=\frac{P(I\&C)}{P(C)}=\frac{0.005}{0.86}= 0.006$

6 0

3 years ago