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Brilliant_brown [7]
3 years ago
8

9+15÷5×13 can someone help me solve this math question ?​

Mathematics
1 answer:
kodGreya [7K]3 years ago
3 0

Answer:

Step-by-step explanation:

The answer is 74

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Solve the following:<br> 2x - 2 = 4x + 6
olchik [2.2K]

Answer:

x = -4

Step-by-step explanation:

<u>Step 1:  Subtract 2x from both sides</u>

2x - 2 - 2x = 4x + 6 - 2x

<em>-2 = 2x + 6</em>

<em />

<u>Step 2:  Subtract 6 from both sides</u>

-2 - 6 = 2x + 6 - 6

<em>-8 = 2x</em>

<em />

<u>Step 3:  Divide both sides by 2</u>

-8 / 2 = 2x / 2

<em>-4 = x</em>

<em />

Answer:  x = -4

5 0
3 years ago
The monthly rental for an apartment is 412.50 how much would the rent be for a year?
gavmur [86]

Answer:

4950

Step-by-step explanation:

412.50 x 12

412.50 is the mothly rental

12 are the month in a year

so it is 4950

8 0
3 years ago
Consider the expression 6n2 + 2n + 3 . What is the coefficient of n?
ad-work [718]

Answer:

Step-by-step explanation:

2

The coefficient is the number in front of the variable.

So, in this case, the coefficient of n^2 is 6 and of n is 2.

6 0
3 years ago
If N is the population of the colony and t is the time in​ days, express N as a function of t. Consider Upper N 0 is the origina
lesya [120]

Answer:

(a)N(t)=Noe^{kt}

(b)5,832 Mosquitoes

(c)5 days

Step-by-step explanation:

(a)Given an original amount N_o at t=0. The population of the colony with a growth rate k \neq 0, where k is a constant is given as:

N(t)=Noe^{kt}

(b)If N_o=1000 and the population after 1 day, N(1)=1800

Then, from our model:

N(1)=1800

1800=1000e^{k}\\$Divide both sides by 1000\\e^{k}=1.8\\$Take the natural logarithm of both sides\\k=ln(1.8)

Therefore, our model is:

N(t)=1000e^{t*ln(1.8)}\\N(t)=1000\cdot1.8^t

In 3 days time

N(3)=1000\cdot1.8^3=5832

The population of mosquitoes in 3 days time will be approximately 5832.

(c)If the population N(t)=20,000,we want to determine how many days it takes to attain that value.

From our model

N(t)=1000\cdot1.8^t\\20000=1000\cdot1.8^t\\$Divide both sides by 1000\\20=1.8^t\\$Convert to logarithm form\\Log_{1.8}20=t\\\frac{Log 20}{Log 1.8}=t\\ t=5.097\approx 5\; days

In approximately 5 days, the population of mosquitoes will be 20,000.

7 0
2 years ago
Read 2 more answers
T + (-5) = 14<br> can someone solve the equation please?
Alja [10]

Answer: 19

Add 5 to both sides

t - 5 = 14

t - 5 + 5 =14 + 5

Simplify

T=19

Hope this helped

4 0
2 years ago
Read 2 more answers
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