Convert this percent into decimal form 3 82-- % same as 82 3/4% 4

Ishaan is 3times as old as Christopher and is also 14 years older than Christopher.

adoni [48]

Ishann is 21 years old.

8 0

3 years ago

The sum of two numbers is 45 and the different is 21.what are the numbers

ryzh [129]

A + b = 45
a - b = 21
a = 21 + b
Use substitution
21 + b + b = 45
2b = 24
b = 12
45 - 12 = 33
The numbers are 33 and 12

6 0

2 years ago

Read 2 more answers

What is (10y+6) (8y-6) ?

ANEK [815]

Answer:

y = 3/4 or y = -3/5

Step-by-step explanation:

Solve for y:

(8 y - 6) (10 y + 6) = 0

Hint: | Find the roots of each term in the product separately.

Split into two equations:

8 y - 6 = 0 or 10 y + 6 = 0

Hint: | Look at the first equation: Factor the left hand side.

Factor constant terms from the left hand side:

2 (4 y - 3) = 0 or 10 y + 6 = 0

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides by 2:

4 y - 3 = 0 or 10 y + 6 = 0

Hint: | Isolate terms with y to the left hand side.

Add 3 to both sides:

4 y = 3 or 10 y + 6 = 0

Hint: | Solve for y.

Divide both sides by 4:

y = 3/4 or 10 y + 6 = 0

Hint: | Look at the second equation: Factor the left hand side.

Factor constant terms from the left hand side:

y = 3/4 or 2 (5 y + 3) = 0

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides by 2:

y = 3/4 or 5 y + 3 = 0

Hint: | Isolate terms with y to the left hand side.

Subtract 3 from both sides:

y = 3/4 or 5 y = -3

Hint: | Solve for y.

Divide both sides by 5:

Answer: y = 3/4 or y = -3/5

4 0

4 years ago

Which is the solution set of the inequality 15 y minus 9 less-than 36 y greater-than nine-fifths y less-than nine-fifths y less-

Vaselesa [24]

Answer:

C. y<3

Step-by-step explanation:

We are required to determine the solution set of the inequality

$15y-9$

Step 1: Add 9 to both sides

$15y-9+9$

Step 2: Divide both sides by 15

$15y \div 15$

The solution set of the given inequality is: y<3.

The correct option is C.

4 0

3 years ago

Read 2 more answers

In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p

Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is $\frac{23}{30}$ or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

$P(A \cup B)=P(A)+P(B)-P(A \cap B)$ ---------------(1)

where

P(A) = Probability of choosing a student playing basket ball

P(B) = Probability of choosing a student playing base ball

P(A \cap B) = Probability of choosing a student playing both the games

Finding P(A)

P(A) = $\frac{\text { Number of students playing basket ball }}{\text{Total number of students}}$

P(A) = $\frac{19}{30}$ --------------------------(2)

Finding P(B)

P(B) = $\frac{\text { Number of students playing baseball }}{\text{Total number of students}}$

P(B) = $\frac{12}{30}$ ---------------------------(3)

Finding $P(A \cap B)$

P(A) = $\frac{\text { Number of students playing both games }}{\text{Total number of students}}$

P(A) = $\frac{8}{30}$ -----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

$P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{31}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{23}{30}$

7 0

3 years ago