Answer:
There were 7 small boxes and 14 large boxes shipped.
Step-by-step explanation:
This problem may be solved by a system of equations:
I am going to say that:
x is the number of small boxes used
y is the number of large boxes used
There were twice as many large boxes shipped as small boxes shipped
This means that y = 2x
Each small box of paper weighs 45 pounds and each large box of paper weighs 80 pounds. The total weight of all boxes was 1435 pounds.
This means that 45x + 80y =1435
So we have to solve the following system:
y=2x
45x + 80y =1435
45x + 80 (2x) = 1435
205x = 1435
x= 1435/205
x=7
y=2x= 2(7) = 14
There were 7 small boxes and 14 large boxes shipped.
3/4x - 16 = 28
+16 +16
3/4x = 44
*3/4 *3/4
x = 176/3
1/4 pound beef, b = $0.75
=》 6 pounds beef = (6)/ (1/4) × b
=》 6 pounds beef = 24 × $0.75 =$18.00
The first is yes and the second is no
The distance traveled is the hypotenuse of the right triangle formed with the ground.
sinα=400/d
d=400/sinα, we are told α=13° so
d=400/sin13 ft
d≈1778ft (to nearest whole foot)
