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Semenov [28]
3 years ago
14

Help please I don’t know it!

Mathematics
1 answer:
Sidana [21]3 years ago
4 0

<em>99kg of water.</em>

<em>Since 100kg of mass = 66kg of water, all you have to do to find a mass of 60 is divide by 2 giving you 50kg of mass, and 33 kg of water. Then add that up onto 100kg of water and 66kg of water to get 150kg of mass and 99kg of water.</em>

<em>Hope this helps you, and have a nice day.</em>

-<em>R3TR0 Z3R0</em>

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Select the correct answer.
Volgvan

Answer:

B

Step-by-step explanation:

If C is the correct answer and if the final result is multiplied out, where does the minus sign in a^4 - b^4 come from? All pluses don't make a minus. A is incorrect.

If D is correct, then a^2 - b^2 should be further factored producing a different kind of answer, like (a + b)^2(c-d)^2 which is not the same as a^4 - b^4. So D is not correct.

The first step in factoring a^4 - b^4 is (a^2 + b^2)(a^2 - b^2) A doesn't lead you anywhere. A is incorrect. The answer must be B.

a^4 - b^4 = (a^2 -  b^2)(a^2 + b^2)  The first term factors.

a4 - b^4 = (a + b)(a - b) (a^2 +b^2)

4 0
4 years ago
The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = (x – 10). What is the stan
ra1l [238]
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4 years ago
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Guys I’m scared to ask my dad for help cus he just helped me and the info went right out the window? Can someone help me? Ik the
N76 [4]

Answer:

  14.  -5√30 +3√2

  15.  18√5 -30√3

Step-by-step explanation:

You can multiply radicals using ...

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And you can simplify radicals using ...

  √(a²b) = a√b

_____

14. Using the distributive property, then simplifying the radicals, we have ...

  \sqrt{3}(-5\sqrt{10}+\sqrt{6})\\\\=-5\sqrt{3\cdot10}+\sqrt{3\cdot6}\\\\=-5\sqrt{30}+\sqrt{3^2\cdot2}\\\\=\boxed{-5\sqrt{30}+3\sqrt{2}}

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15. Similarly, ...

  -2\sqrt{15}(-3\sqrt{3}+3\sqrt{5})\\\\=6\sqrt{15\cdot3}-6\sqrt{15\cdot5}\\\\=6\sqrt{3^2\cdot5}-6\sqrt{5^2\cdot3}\\\\=\boxed{18\sqrt{5}-30\sqrt{3}}

5 0
4 years ago
Two identical metal spheres at 8 °C are put in equal amount of water in two beakers, as shown below.
eduard

Answer:

\boxed{ \text{The temperature of the water in Beaker A will increase.}}

Step-by-step explanation:

Heat always flows from a hotter object to a colder one. If heat flows from the sphere to the water, \boxed{\textbf {the temperature of the water will increase.}}

A is wrong. If the temperature of the water is greater than 8 °C, heat will flow from the water to the sphere.

B is wrong. If the temperature of the water is lower than 8 °C, heat will flow from the sphere to the water..

D is wrong.  If heat flows from the water to the sphere, the temperature of the water will decrease.

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Answer:

A.

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