9514 1404 393
Answer:
y = -x -12
Step-by-step explanation:
The slope of the line you want is the same as the slope of the line you have: -1. Then the point-slope equation of the line is ...
y -k = m(x -h) . . . . . . line of slope m through point (h, k)
y -(-7) = -1(x -(-5))
y = -x -5 -7 . . . . subtract 7, eliminate parentheses
y = -x -12 . . . slope-intercept equation
Answer:
Step-by-step explanation:
Hello!
The standard deviation (δ) is a measure of variability, this means, it shows how dispersed the data set is with respect to the mean. The population mean (μ) is a measurement of position. The three graphics have the same position μ=0 but their standard deviations change, this means, the form of their bells is different. The greater the value of the standard deviation, the more dispersed the data is you can see this graphically because the width of the bell will be greater.
Graph attached.
I hope it helps!
<h3>Answer:</h3>
- white : brown = 8 : 5
- black : total = 6 : 23
<h3>Explanation:</h3>
Each of the ratio components (white socks, brown socks, black socks, total socks) has an associated number (8, 5, 6, 23). Write the desired ratio using the associated numbers.
The given angles are complementary, therefore:
(5r + 5) + (8r -6) = 90°
13r - 1 = 90
13r - 1 + 1 = 90 + 1
13r = 91
13r/13 = 91/13
r = 7
<h3>Answer:</h3>
- ABDC = 6 in²
- AABD = 8 in²
- AABC = 14 in²
<h3>Explanation:</h3>
A diagram can be helpful.
When triangles have the same altitude, their areas are proportional to their base lengths.
The altitude from D to line BC is the same for triangles BDC and EDC. The base lengths of these triangles have the ratio ...
... BC : EC = (1+5) : 5 = 6 : 5
so ABDC will be 6/5 times AEDC.
... ABDC = (6/5)×(5 in²)
... ABDC = 6 in²
_____
The altitude from B to line AC is the same for triangles BDC and BDA, so their areas are proportional to their base lengths. That is ...
... AABD : ABDC = AD : DC = 4 : 3
so AABD will be 4/3 times ABDC.
... AABD = (4/3)×(6 in²)
... AABD = 8 in²
_____
Of course, AABC is the sum of the areas of the triangles that make it up:
... AABC = AABD + ABDC = 8 in² + 6 in²
... AABC = 14 in²