B is the answer
you buy more when it is on sale
Solution :
Given :
The events are as follows :
P : Set of all the people
S : Set of people those who are single
C : Set of people having children
W : Set of women
M : Set of men
a). Now set of married women having children is given by :

And set of single women who do not have any children : (S -C) - M
Thus the set of women those who are either married and have children or they are single and they do not have any children is represented by :

b). Set of Married men : 
Set of Married men : 
Set of all possible married who are heterosexual couples, that is, all possible pairings of the married men and the married women is represented by :

c). The number of all the possible married heterosexual couples will be represented by the cardinality of the above set, which represents the number of the elements in the set.
Thus the number of the married heterosexual couples is given by :
![$n[((P-S) \cap M) \cap ((P-S) \cap W)]$](https://tex.z-dn.net/?f=%24n%5B%28%28P-S%29%20%5Ccap%20M%29%20%5Ccap%20%28%28P-S%29%20%5Ccap%20W%29%5D%24)
Answer:
Answer should be x^9
Step-by-step explanation:
This equation looks really complicted, but it's actually much easier when you break it down! First, your going to multiply the fraction 3/2 by 6 - since one is a fraction, youre going to find the GCF, or Greatest Common Factor, and reduce it. The GCF in this equation is 2, so we eliminate the two from the fraction (making it just 3) and divide 6 by 2 (getting 3). Thus, we are left with (x^3)^3 -> 3 x 3 = 9. So we are left with x^9. I hope this helps!