Set up the given triangle on x-y coordinates with right angle at (0,0). So the two vertices are at (5,0) and (0,2
![sqrt{x} n]{3}](https://tex.z-dn.net/?f=sqrt%7Bx%7D%20n%5D%7B3%7D%20)
)
let (a,0) and (0,b) be two vertices of the<span> equilateral triangle. So the third vertex must be at </span>

for a pt (x,y) on line sx+ty=1, the minimum of

equals to

smallest value happens at

so area is

hence m=75, n=67, p=3
m+n+p = 75+67+3 = 145
The answer is A
.................
Answer:
The answer is 135 degrees.
Step-by-step explanation:
As we are given the position. If we take the <u>derivative</u>, we get the velocity vector. If we take the <u>derivative</u> again, we find the acceleration vector of the particle.



At time t=0;


As i attach in the picture the angle between the velocity and acceleration vector is
degrees
<u>Answer:</u>
The geometric mean between each pair of numbers 
<u>Solution:</u>
The Geometric mean between two numbers a and b is given as Geometric mean =
--- eqn 1
The Geometric Mean is a special type of average where we multiply the numbers together and then take a square root for the numbers.
From question, given that two numbers are 
Hence we can say “a” =
=7
Similarly “b” =
= 29
We have to find the geometric mean between “7” and “29”
By using equation 1,
Geometric mean between 7 and 29 =
= 14.24
Hence the geometric mean between 