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Alona [7]
2 years ago
14

Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = 3x2 − 2x + 1, [0, 2] Yes, it do

es not matter if f is continuous or differentiable, every function satisfies the Mean Value Theorem. Yes, f is continuous on [0, 2] and differentiable on (0, 2) since polynomials are continuous and differentiable on . No, f is not continuous on [0, 2]. No, f is continuous on [0, 2] but not differentiab
Mathematics
1 answer:
expeople1 [14]2 years ago
4 0

Answer:

Yes , function is continuous in [0,2] and is differentiable (0,2) since polynomial function are continuous and differentiable

Step-by-step explanation:

We are given the Function

f(x) =3x^2 -2x +1

The two basic hypothesis of the mean valued theorem are

  • The function should be continuous in [0,2]
  • The function should be differentiable in (1,2)

upon checking the condition stated above on the given function

f(x) is continuous in the interval [0,2] as the functions is quadratic and we  can conclude that from its graph

also the f(x) is differentiable in (0,2)

f'(x) = 6x - 2

Now the function satisfies both the conditions

so applying MVT

6x-2 = f(2) - f(0) / 2-0

6x-2 = 9 - 1 /2

6x-2 = 4

6x=6

x=1

so this is the tangent line for this given function.

   

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Step-by-step explanation:

4 0
3 years ago
The ordered pair (36,4) is a solution to what equation?
andreyandreev [35.5K]
Y=X/9

If you plug in the point:

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Hope this helps!
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3 years ago
13.92 x 2.7≈ What’s the answer?
AlexFokin [52]

Answer:

37.584

Step-by-step explanation:

Hope this helps

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3 years ago
Given f(x)= 3x^2-5x+2 and g(x)= 4x- 6, find f(x)+g(x).
kirill115 [55]

f(x) = 3x² - 5x + 2

g(x) = 4x - 6


f(x) + g(x)


(3x²- 5x + 2) + (4x - 6)

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3 years ago
I need help with the question
Katena32 [7]

Answer:

6, 8, 4

Step-by-step explanation:

the answers are as follows

a. 6

b. 8

c. 4

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