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postnew [5]
3 years ago
12

"A number subtracted from 14 is 2."​

Mathematics
2 answers:
Makovka662 [10]3 years ago
8 0
I believe that 12 is the correct answer
V125BC [204]3 years ago
4 0

Answer:

12

Step-by-step explanation:

we introduce an unknown x

14-x=2

-x=2-14

-x=-12

x=12

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Help please if you can will give branliest
Yuliya22 [10]

Answer:

i’m thinking it might be 10?

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Suppose a certain character in a role-playing game has an ability to use in battles. When activated, the ability deals damage to
Helen [10]

Answer:

The chance of getting exactly 3 hits is =  0.20

Step-by-step explanation:

P.S - The exact question is -

As given,

F(x) = 0 ,          x < 1

         0.30 ,     1  ≤ x < 2

         0.56 ,     2 ≤ x < 3

         0.76 ,     3 ≤ x < 4

         0.9 ,       4  ≤ x < 5

         1 ,            5  ≤ x

Now,

f(x) = 0.30 ,                            x = 1

        0.56 - 0.30 = 0.26 ,     x = 2

         0.76 - 0.56 = 0.20 ,     x=3

         0.9 - 0.76 = 0.14  ,       x = 4

         1 - 0.9 = 0.1 ,                 x = 5

          0,                                 otherwise

Now,

The chance of getting exactly 3 hits is = f(x = 3) = 0.20

8 0
3 years ago
Factor −1/3 out of −1/3x−8.
Gnom [1K]

For this case we have the following expression:

- \frac {1} {3} x-8

We take common factor - \frac {1} {3}, for this we must take into account that:

- * + = -\\\frac {24} {3} = 8

So, factoring the expression we have:

- \frac {1} {3} (x + 24)

ANswer:

The factored expression is:

- \frac {1} {3} (x + 24)

8 0
3 years ago
Darren wants to estimate the mean age in a population of trees. He'll sample nnn trees and build a 90\%90%90, percent confidence
Alchen [17]

Using the z-distribution, as we have the standard deviation for the population, it is found that the smallest sample size required to obtain the desired margin of error is of 77.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

The margin of error is given by:

M = z\frac{\sigma}{\sqrt{n}}

In this problem, we have that the parameters are given as follows:

M = 3, z = 1.645, \sigma = 16.

Hence, solving for n, we find the sample size.

M = z\frac{\sigma}{\sqrt{n}}

3 = 1.645\frac{16}{\sqrt{n}}

3\sqrt{n} = 1.645 \times 16

\sqrt{n} = \frac{1.645 \times 16}{3}

(\sqrt{n})^2 = \left(\frac{1.645 \times 16}{3}\right)^2

n = 76.97

Rounding up, the smallest sample size required to obtain the desired margin of error is of 77.

More can be learned about the z-distribution at brainly.com/question/25890103

4 0
2 years ago
How many times does4× 8 go into 12×12 ​
blsea [12.9K]

4x8=32 12x12=144 32 goes into 144 4.5 times

4 0
4 years ago
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