All categories

2 years ago

Sam bought a Blu-ray disc for $20.00 plus sales tax of 8%. What was the amount of tax paid?

Mathematics

2 answers:

Lapatulllka [165]2 years ago

8 0

Answer: Sales Tax Together is $21.60 the sales tax alone is $1.60

Step-by-step explanation:

allochka39001 [22]2 years ago

4 0

Answer:

21.60

Step-by-step explanation:

You might be interested in

The equation y = 11x shows that a boat travels at a speed of 11 km/h. Which ordered pair satisfies the equation y = 11x?

Arada [10]

(0,0)
(0.1, 1.1)
(0.5, 5.5)
(0.8, 8.8)
(1,11)
(2,22)
(3,33)
(4,44)
(5,55)
(10,110)
(11, 121)
(20, 220)
(30, 330)
(90, 990)

etc, etc

3 0

3 years ago

Solve for d 3(d+12)=8-4d ?????

zysi [14]

Answer:

d=-4

Step-by-step explanation:

the answer is negative 4 have a nice day :)

5 0

3 years ago

Three students were given the expression shown and were asked to take a common factor out of two of the terms. Use the drop-down

Tomtit [17]

Answer:

Calvin: incorrect, sign error

Greg: incorrect, has no relationship to the given expression

Ruben: incorrect, sign error

Equivalent expression: 7 92(4x -11)

Step-by-step explanation:

I hope this helps you :)

-KeairaDickson

3 0

3 years ago

HURRY WILL MARK BRAINLIEST

NNADVOKAT [17]

Answer:

Step-by-step explanation:

A parabola opening up will have a positive value for the a value in ax^2+bx+c form. Also, the larger the absolute value of the a value, the more narrow the parabola will appear.

Hope this helps!

4 0

3 years ago

Read 2 more answers

GCSE 995381

nikdorinn [45]

Answer:

$2.9 cm^2$

Step-by-step explanation:

Given,

Angle of sector = 30°

Radius of circle, r = 8 cm

Area of the shaded region, A =?

The diagram is attached below.

Now,

Area of shaded region = Area of sector - Area of triangle

Area of triangle = $\frac{1}{2}\times base \times height$

We know that,

$\sin \theta = \dfrac{P}{H}$

$\sin 30^\circ= \dfrac{P}{8}$

$P = \dfrac{8}{2}$

$P = 4\ cm$

And

$\cos \theta =\dfrac{B}{H}$

$\cos 30^\circ = \dfrac{B}{8}$

$B = \dfrac{8\times \sqrt{3}}{2}$

$B = 4\sqrt 3$

Area of sector = $\dfrac{\theta}{360^\circ}\times \pi r^2$

Area of sector = $\dfrac{30^\circ}{360^\circ}\times \pi \times 8^2$

= 16.75 cm^2

Area of triangle = $\dfrac{1}{2} \times 4\sqrt 3 \times 4$

= 13.85 cm^2

Area of shaded region = 16.75 - 13.85

= $2.9 cm^2$

7 0

2 years ago