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Sever21 [200]
3 years ago
13

HELP ME PLEASE SOMEONE !!

Mathematics
1 answer:
zzz [600]3 years ago
6 0

Answer: A

Step-by-step explanation:

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In slope intercept form (y=mx+b) what is the "m"?<br> Pls help
Brut [27]

Answer:

m is the slope

Step-by-step explanation:

5 0
3 years ago
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The final balance in an account that has a monthly fee and automatic monthly deposits is given by the expression. The initial ac
trapecia [35]
150x represents the monthly deposit, and -4.99 represents the monthly fee.
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4 years ago
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What is the area in square meters of the trapezoid below​
Rina8888 [55]

Given:

Bases of the trapezoid are 5.2 m and 14.6 m.

The height of the trapezoid is 7 m.

To find:

The area of the trapezoid.

Solution:

The area of a trapezoid is:

A=\dfrac{a+b}{2}\times h

Where, a,b are bases and h is the height of the trapezoid.

Putting a=5.2,b=14.6,h=7 in the above formula, we get

A=\dfrac{5.2+14.6}{2}\times 7

A=\dfrac{19.8}{2}\times 7

A=9.9\times 7

A=69.3

Therefore, the area of the trapezoid is 69.3 square meters.

3 0
3 years ago
64^x = 16^ x - 1<br><br> A: -2<br> B: -1<br> C: -1/4<br> D: -1/3
Murljashka [212]

Answer:

c

Step-by-step explanation:

64/3

8 0
3 years ago
Use part 1 of the fundamental theorem of calculus to find the derivative of the function. y = cos x (3 + v5)8 dv sin x
dexar [7]
It looks like

y(x)=\displaystyle\int_{\cos x}^{\sin x}(3+v^5)^8\,\mathrm dv

(If the limits are in the wrong order, just multiply the result by -1)

Split the integral at an arbitrary value between \cos x and \sin x, and write y(x) as

y(x)=\displaystyle\left\{\int_{\cos x}^c+\int_c^{\sin x}\right\}(3+v^5)^8\,\mathrm dv

y(x)=\displaystyle\int_c^{\sin x}(3+v^5)^8\,\mathrm dv-\int_c^{\cos x}(3+v^5)^8\,\mathrm dv

Then by the FTC,

\dfrac{\mathrm dy}{\mathrm dx}=(3+\sin^5x)^8\cdot\dfrac{\mathrm d\sin x}{\mathrm dx}-(3+\cos^5x)^8\cdot\dfrac{\mathrm d\cos x}{\mathrm dx}

\dfrac{\mathrm dy}{\mathrm dx}=\cos x(3+\sin^5x)^8+\sin x(3+\cos^5x)^8
7 0
4 years ago
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