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Y_Kistochka [10]
2 years ago
8

The sum of two consecutive even numbers is eighteen.

Mathematics
1 answer:
Scilla [17]2 years ago
5 0

Answer:

8 and 10

Step-by-step explanation:

8+10=18

Both are even, and consecutive

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Step-by-step explanation:

The length of the hypotenuse is ten.

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15 different tasks are assigned to 8 different people. There are no restrictions on the number of tasks that can be given to any
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Answer:

3.52 * 10^{13}ways

Step-by-step explanation:

Since 1 task can be assigned to 1 person, we can start by assigning people to the task. There are 15 different task, so at the first task there are 8 choices, at the 2nd task there are also 8 choices, and so on. There's also the fact that these tasks are all different.

Therefore the total number of way to assign 8 people to 15 tasks is

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2 years ago
The sum of two polynomials is 10a^2b^2-8a^2b+6ab^2-4ab+2 if one addend is -5a^2b^2+12a^2b-5 what is the other addend
spayn [35]

Answer:

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Step-by-step explanation:

The other addend is determined by subtracting -5\cdot a^{2}\cdot b^{2}+12\cdot a^{2}\cdot b-5 from 10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a\cdot b^{2}-4\cdot a \cdot b + 2:

x = 10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b + 2 - (-5\cdot a^{2}\cdot b^{2}+12\cdot a^{2}\cdot b -5)

x = 10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +2 +5\cdot a^{2}\cdot b^{2}-12\cdot a^{2}\cdot b+5

x = (10\cdot a^{2}\cdot b^{2}+5\cdot a^{2}\cdot b^{2})-(8\cdot a^{2}\cdot b+12\cdot a^{2}\cdot b)+6\cdot a \cdot b^{2}-4\cdot a \cdot b +7

x = 15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7

The other addend is 15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7.

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