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3 years ago

10

Stuck on these questions. any help? (last word missing is degree)

1 answer:

nignag [31]3 years ago

4 0

Answer: x^3 - 3x^2 + 2x

Step-by-step explanation:

Zeros 0, 1, 2

f(x)= x (x-1)(x-2)

= x (x^2 - 3x + 2)

= x^3 - 3x^2 + 2x

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Find out the answers to this

meriva

Answer:

$\tan \theta = - \frac{1}{5} = - 0.2$

$\cos \theta = 0.98$

$\sin \theta = - 0.196$

Step-by-step explanation:

It is given that $\cot \theta = - 5$ and $\theta$ is in the fourth quadrant.

So, only $\cos \theta$ will have positive value and $\sin \theta$ , $\tan \theta$ will have negative value.

Now, $\cot \theta = - 5$

⇒ $\tan \theta = \frac{1}{\cot \theta} = -\frac{1}{5}$ (Answer)

We know, that $\sec^{2} \theta - \tan^{2} \theta = 1$

⇒ $\sec \theta = \sqrt{1 + \tan^{2} \theta } = \sqrt{1 + (- \frac{1}{5} )^{2} } = 1.019$

{Since, $\cos \theta$ is positive then $\sec \theta$ will also be positive}

⇒ $\cos \theta = \frac{1}{\sec \theta} = \frac{1}{1.0198} = 0.98$ (Answer)

We know, that $\csc^{2} \theta - \cot^{2} \theta = 1$

⇒ $\csc \theta = - \sqrt{1 + \cot^{2} \theta } = - \sqrt{1 + (- 5 )^{2} } = - 5.099$

{Since, $\sin \theta$ is negative then $\csc \theta$ will also be negative}

⇒ $\sin \theta = \frac{1}{\csc \theta} = \frac{1}{- 5.099} = - 0.196$ (Answer)

4 0

3 years ago

Solve the following equation. | x + 3 | = 4

Lelechka [254]

Answer:

x1= -7 , x2= 1

Step-by-step explanation:

8 0

3 years ago

Pls show work thank you!!!

Nastasia [14]

$|-16-x|=0\\\\\implies -16-x = 0\\\\\implies x = -16$

8 0

2 years ago

On a survey eight students reported how many minutes it takes them to travel to school here are there responses 9, 11, 3, 14, 14

Triss [41]

Hi!

The answer to your question is 9.75 minutes

Here is the math to prove it:

9+11+3+14+14+7+14+6=78

Now you will take 78 and divide it by 8

This is because when finding the mean you add all of the given number together and then divide them by the amount of number added together.

78/8=9.75

Thus, your answer is 9.75 minutes

I hope this helped!

Have a wonderful day/night!

God bless!

8 0

2 years ago

I need some help on this triangle similarity proof in Geometry!

AlladinOne [14]

I believe that this is correct if anything is unclear/blurry just ask and i will tell u what i wrote

8 0

3 years ago