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lisov135 [29]
3 years ago
6

Help now plz just help plzzz

Mathematics
1 answer:
zalisa [80]3 years ago
8 0

Answer:

there is no problem

Step-by-step explanation:

sorry

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Anyone help me solve for y.
riadik2000 [5.3K]

Answer:

y = - 4

Step-by-step explanation:

Given

y = 2x + ( - 2) , that is

y = 2x - 2 ← substitute x = - 1

y = 2(- 1) - 2 = - 2 - 2 = - 4

This is confirmed by the point (- 1, - 4 ) on the graph

3 0
3 years ago
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How do i solve for x
Dafna11 [192]

The letter "x" is often used in algebra to mean a value that is not yet known. It is called a "variable" or sometimes an "unknown". In x + 2 = 7, x is a variable, but we can work out its value if we try! so im pretty sure its 20

5 0
3 years ago
Can someone plz help me answer this asap<br> due today plz <br> 8+x−6−5=8x+1−3x
kykrilka [37]

Isolate the variable by dividing each side by factors that don't contain the variable.
x = −1
4 0
3 years ago
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I need help it due today
Alisiya [41]

Answer:

1st box: Asso. prop= m+(4+x)

2nd box: Comm. Prop= m+4=4+m

3rd box: iden. prop= m+0=m

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4 0
3 years ago
find the probability of being delt 5 clubs and 3 cards with one of each remaining suit in 8 card poker
kumpel [21]

Answer: 0.003757(approx).

Step-by-step explanation:

Total number of combinations of selecting r things out of n things is given by:-

^nC_r=\dfrac{n!}{r!(n-r)!}

Total cards in a deck = 52

Total number of ways of choosing 8 cards out of 52 = ^{52}C_8

Total number of ways to choose 5 clubs and 3 cards with one of each remaining suit = ^{13}C_5\times^{13}C_1\times^{13}C_1\times^{13}C_1  [since 1 suit has 13 cards]

The required probability = =\dfrac{^{13}C_5\times^{13}C_1\times^{13}C_1\times^{13}C_1}{^{52}C_8}

=\dfrac{\dfrac{13!}{5!8!}\times13\times13\times13}{\dfrac{52!}{8!44!}}\\\\=\dfrac{24167}{6431950}\\\\\approx0.003757

Hence, the required probability is 0.003757 (approx).

5 0
3 years ago
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