Complete the square to rewrite the quadratic:
2 <em>x</em>² + 3 <em>x</em> + 5 = 2 (<em>x</em>² + 3/2 <em>x</em>) + 5
... = 2 (<em>x</em>² + 3/2 <em>x</em> + 9/16 - 9/16) + 5
... = 2 (<em>x</em>² + 3/2 <em>x</em> + (3/4)²) + 5 - 9/8
... = 2 (<em>x</em> + 3/4)² + 31/8
Any real number squared becomes non-negative, so the quadratic expression has a minimum value of 31/8, which is greater than 0, and so there are no (real) <em>x</em> for which <em>y</em> = 0.
Answer:
Step-by-step explanation:
3.5805
Answer:
9/50
Step-by-step explanation:
There are nine single digit numbers from integers 1-50 so in order to calculate the probability of getting 3 random numbers from 1-50 to be single digits:
Probability = number of favorable outcomes /total number of outcomes
Therefore Probability of getting 3 single digits randomly from 1-50 = 9/50
