A fair charges $7.25 for admission and $5.50 for a ride pass. Ten friends visited the fair. Not all of the friends purchased rid e passes. If their total cost was $105.50, how many friends purchased ride passes? tell me pls thank you
2 answers:
<h2>
Answer: </h2>
The number of friends who purchased ride passes= 6
<h2>
Step-by-step explanation: </h2>
It is given that:
A fair charges $7.25 for admission and $5.50 for a ride pass.
Now, if 10 friends visited the fair.
This means that:
Total cost of admission= 7.25×10= $ 72.5
Also, if x friends purchased the ride passes.
Then, the total cost of ride passes= 5.50x
Total cost= 72.5+5.50x
This means that:
72.5+5.50x=105.50
i.e.
5.50x=105.50-72.5
5.50x=33
x=33/5.50
x=6
Hence, 6 friends purchased ride passes.
You take 7.25 (10)+5.5p=105.5 72.5+5.5p=105.5 To make the equation easier multiply the whole equation by ten like this (72.5+5.5p=105.5)10 that equals 725+55p=1055 Then subtract 725 to both sides 725+55p=1055 -725 -725 ____ _____ 55p=330 Then divide by 55 on both sides and that equals 6 so 6 people bought tickets
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