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ankoles [38]
3 years ago
15

A fair charges $7.25 for admission and $5.50 for a ride pass. Ten friends visited the fair. Not all of the friends purchased rid

e passes. If their total cost was $105.50, how many friends purchased ride passes?
tell me pls thank you
Mathematics
2 answers:
Irina18 [472]3 years ago
4 0
<h2>Answer:</h2>

The number of friends who purchased ride passes= 6

<h2>Step-by-step explanation:</h2>

It is given that:

A fair charges $7.25 for admission and $5.50 for a ride pass.

Now, if 10 friends visited the fair.

This means that:

Total cost of admission= 7.25×10= $ 72.5

Also, if x friends purchased the ride passes.

Then, the total cost of ride passes= 5.50x

Total cost= 72.5+5.50x

This means that:

72.5+5.50x=105.50

i.e.

5.50x=105.50-72.5

5.50x=33

x=33/5.50

x=6

     Hence, 6 friends purchased ride passes.

kati45 [8]3 years ago
3 0
You take
7.25 (10)+5.5p=105.5
72.5+5.5p=105.5
To make the equation easier multiply the whole equation by ten like this
(72.5+5.5p=105.5)10 that equals
725+55p=1055
Then subtract 725 to both sides
725+55p=1055
-725 -725
____ _____
55p=330
Then divide by 55 on both sides and that equals 6 so 6 people bought tickets
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