Let
x------> Cathy's<span> ages
</span>y------> Tony's ages
we know that
x+y=65-----> x=65-y-----> equation 1
y-8=(2/5)*(x-8)-----> equation 2
substitute equation 1 in equation 2
y-8=(2/5)*(65-y-8)---> y-8=22.8-0.4y----> y+0.4y=22.8+8
1.4y=30.8-----> y=22
x=65-y-----> x=65-22----> x=43
the answer is
Cathy's ages is 43 years
Tony's ages is 22 years
Answer:
This problem requires us to calculate, the value of investment after 10 and 25 years, and also tell the time after which intial investment amount will double. Investment rate and initial investment amount is given in the question.
Value of investment after 10 year = 600(1+8%)^10 = $ 1,295
Value of investment after 25 year = 600(1+8%)^25 = $ 4,109
Time after which investment amount double (n)
1200 = 600 (1.08)^n
Log 2 = n log 1.08
n = 9 years
Answer:1
Step-by-step explanation:
Answer:
X = 4
I hope this helps
if you could, feel free to mark me Brainliest it would be much appreciated :D
There asking what the numbers are by The ratios, what I did was did was multiply by 8 for each number 8•8=64 13•8=104 11•8=88 so now what you do is add up 64+104+88=256 those are your answers if you want to double check you will dived them by 8 so 64/8=8 104/8=13 88/8=11
Hope this helps :-)
