On the X side it’s +1
Hopefully this helps
I think thats how ur welcome
Plug the points into the equation.
Ex. y=3x-5
(X,y)
1. (5,10): 10=3(5)-5
15-5=10; point 1 is valid
-1=3(-2)-5
-1=-6-5
-1 does not equal -11
Point 2 is not valid
Same process for letter B
Answer:
y+3= -6(x+9) is the answer
Step-by-step explanation:
Answer:
Step-by-step explanation:
The given quadratic must be rewritten in standard form before anything else is done: -2x^2 + 8x - 8 = 0. The coefficients of the x terms are {-2, 8, -8}.
The discriminant b^2 - 4ac is therefore (8)^2 - 4(-2)(-8), or 64 - 64, or 0.
A zero discriminant points to two real, equal solutions.
