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Verizon [17]
3 years ago
14

One base of an isosceles trapezoid is 12 and the other is 20. What is the length of the midsegment?

Mathematics
1 answer:
mr_godi [17]3 years ago
6 0
The length of the midsegment of an isosceles trapezoid is the sum of the two bases, divided by 2. So this means -

(base 1+base2) / 2

(12+20) / 2

32/2

Length of midsegment = 16
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4 0
3 years ago
D = 3.2(t+1)(2t - 3)
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Answer:

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Step-by-step explanation:

Equate d=0 and solve the expression, t=-1 and 3/2 but t can't be negative.

8 0
3 years ago
Rewrite the expression below.<br><br> -2a( a + b - 5)+ 3 (-5a + 2b) +b (6a + b - 8)
Paul [167]

Answer:

b^2 + 4 a b - 2 b - 2 a^2 + -5 a

Step-by-step explanation:

Simplify the following:

-2 a (a + b - 5) + 3 (2 b - 5 a) + b (6 a + b - 8)

-2 a (-5 + a + b) = 10 a - 2 a^2 - 2 a b:

10 a - 2 a^2 - 2 a b + 3 (2 b - 5 a) + b (6 a + b - 8)

3 (2 b - 5 a) = 6 b - 15 a:

10 a - 2 a^2 - 2 a b + 6 b - 15 a + b (6 a + b - 8)

b (-8 + 6 a + b) = -8 b + 6 a b + b^2:

10 a - 2 a^2 - 2 a b - 15 a + 6 b + -8 b + 6 a b + b^2

Grouping like terms, 10 a - 2 a^2 - 2 a b - 15 a + 6 b - 8 b + 6 a b + b^2 = b^2 + (6 a b - 2 a b) + (6 b - 8 b) - 2 a^2 + (10 a - 15 a):

b^2 + (6 a b - 2 a b) + (6 b - 8 b) - 2 a^2 + (10 a - 15 a)

a b 6 + a b (-2) = 4 a b:

b^2 + 4 a b + (6 b - 8 b) - 2 a^2 + (10 a - 15 a)

6 b - 8 b = -2 b:

b^2 + 4 a b + -2 b - 2 a^2 + (10 a - 15 a)

10 a - 15 a = -5 a:

Answer:  b^2 + 4 a b - 2 b - 2 a^2 + -5 a

8 0
3 years ago
Please help.
Mariulka [41]

Step-by-step explanation:

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Example:

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5 0
4 years ago
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RSB [31]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
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