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Verizon [17]
3 years ago
14

One base of an isosceles trapezoid is 12 and the other is 20. What is the length of the midsegment?

Mathematics
1 answer:
mr_godi [17]3 years ago
6 0
The length of the midsegment of an isosceles trapezoid is the sum of the two bases, divided by 2. So this means -

(base 1+base2) / 2

(12+20) / 2

32/2

Length of midsegment = 16
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What is <br><br>r+15=36<br><img src="https://tex.z-dn.net/?f=r%20%2B%2015%20%3D%2036" id="TexFormula1" title="r + 15 = 36" alt="
Blizzard [7]

Answer:

Step-by-step explanation:

R=21

6 0
3 years ago
Write the equation for a parabola with a focus at (-8, -1) and a directrix at y = − 4.
Sidana [21]

Answer:

y = 1/6 x^2 + 8/3 x + 49/6

Step-by-step explanation:

This is a parabola which opens upwards.

The distance of a point (x, y)  from the focus is

√[(x -  -8)^2  + (y - -1)^2] and

the distance of the point from the line y = -4

= y - -4

These distances are equal for a parabola so:

√[(x -  -8)^2  + (y - -1)^2] = y + 4

Squaring both sides:

(x + 8)^2 + (y + 1)^2  = (y + 4)^2

x^2 + 16x + 64 + y^2 + 2y + 1 = y^2 + 8y + 16

x^2 + 16x + 64 + 1 - 16 = 8y - 2y

6y = x^2 + 16x + 49

y = 1/6 x^2 + 8/3 x + 49/6 is the equation of the parabola.

4 0
3 years ago
How do you find the minimum? It says the answer but I’m not sure how it is (4,-4)
Brilliant_brown [7]

Answer:

You could use a graphing calculator to see the lowest point in the graph OR you could put that equation into it's completed squared form, which is (x-4)^2 -4. The opposite of -4 in the parentheses is positive 4, and the leftover -4 is the y value. So that also becomes (4,-4)

8 0
3 years ago
(Angle/triangle problem 25points)<br> What is the value of X?
Serhud [2]

Answer:

x = 5

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Sum the 3 angles in the triangle and equate to 180, that is

10x - 4 + 8x + 3 + 91 = 180

18x + 90 = 180 ( subtract 90 from both sides )

18x = 90 ( divide both sides by 18 )

x = 5


3 0
3 years ago
The graph above is a transformation of the function x2 Write an equation for the function graphed above
lutik1710 [3]

Answer: y=0,5x²-x-1,5.

Step-by-step explanation:

(-1;0)\ \ \ \ (3;0)\ \ \ \ (1;-2)   \ \ \ \  y=ax^2+bx+c\ ?\\\left\{\begin{array}{ccc}a*(-1)^2+b*(-1)+c=0\\a*3^2+b*3+c=0\\a*1^2+b*1+c=-2\end{array}\right \ \ \ \  \ \left\{\begin{array}{ccc}a-b+c=0\ \ (1)\\9a+3b+c=0\ (2)\\a+b+c=-2\ (3)\end{array}\right  \\

We summarize (1) and (3):

2a+2c=-2\ |:2\\a+c=-1\ \ \ \ \Rightarrow\\a+b+c=-2\\(a+s)+b=-2\\-1+b=-2\\b=-1.

Substitute b=-1 into (2):

9a+3*(-1)+c=0\\9a-3+c=0\\9a+c=3\ \ (5).\\

From (5) subtract (4):

8a=4\ |:8\\a=0,5.\ \ \ \  \Rightarrow\\

Substitute a=0,5 into (4):

0,5+c=-1\\c=-1,5.

Hense:

y=0,5x²-x-1,5.

5 0
2 years ago
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