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Eva8 [605]
3 years ago
10

Part A: Factor 3x2y2 − xy2 − 2y2. Show your work. (4 points) Part B: Factor x2 + 6x + 9. Show your work. (3 points) Part C: Fact

or x2 − 25. Show your work. (3 points)
Mathematics
1 answer:
san4es73 [151]3 years ago
4 0
A)  the greatest common factor is y^2 so

y^2(3x^2-x-2)

...

B)  x^2+6x+9

x^2+3x+3x+9

x(x+3)+3(x+3)

(x+3)(x+3)

(x+3)^2

C)

x^2-25

x^2-5x+5x-25

x(x-5)+5(x-5)

(x+5)(x-5)
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Answer:

At 53 mph, he traveled for 1.5 hours

At 58 mph, he traveled for 2 hours

Step-by-step explanation:

Mathematically;

distance = speed * time

let the time for the first part of the trip be x hours and the second part be y hours

Total hours is 3.5

So therefore;

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Now let’s work with the rate

53 mph for x hours = 53 * x = 53x miles

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Adding both;

53x + 58y = 195.5 miles ••••••••(ii)

We have two equations to solve simultaneously

From i, x = 3.5 - y

insert into ii

53(3.5-y) + 58y = 195.5

185.5 - 53y + 58y = 195.5

5y = 195.5-185.5

5y = 10

y = 10/5

y = 2 hours

x = 3.5 - y

x = 3.5 - 2

x = 1.5 hours

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