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Eva8 [605]
3 years ago
10

Part A: Factor 3x2y2 − xy2 − 2y2. Show your work. (4 points) Part B: Factor x2 + 6x + 9. Show your work. (3 points) Part C: Fact

or x2 − 25. Show your work. (3 points)
Mathematics
1 answer:
san4es73 [151]3 years ago
4 0
A)  the greatest common factor is y^2 so

y^2(3x^2-x-2)

...

B)  x^2+6x+9

x^2+3x+3x+9

x(x+3)+3(x+3)

(x+3)(x+3)

(x+3)^2

C)

x^2-25

x^2-5x+5x-25

x(x-5)+5(x-5)

(x+5)(x-5)
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Given that x square + 5 x + c is a perfect square find the value of C ​
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Answer:

c = \frac{25}{4}

Step-by-step explanation:

To make a perfect square

add ( half the coefficient of the x- term )² to x² + 5x

x² + 5x + (\frac{5}{2} )²

= x² + 5x + \frac{25}{4}

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5 0
3 years ago
Look at the image. (calculus)
mash [69]
<h3>Answer: Choice H)  2</h3>

=============================================

Explanation:

Recall that the pythagorean trig identity is \sin^2 x + \cos^2x = 1

If we were to isolate sine, then,

\sin^2 x + \cos^2x = 1\\\\\sin^2 x = 1-\cos^2x\\\\\sin x = \sqrt{1-\cos^2x}\\\\

We don't have to worry about the plus minus because sine is positive when 0 < x < pi/2.

Through similar calculations, \cos x = \sqrt{1-\sin^2x}\\\\

Cosine is also positive in this quadrant.

-------------

So,

\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}\\\\\frac{\sin x}{\sin x}+\frac{\cos x}{\cos x}\\\\1+1\\\\2

Therefore,

\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}=2

is an identity as long as 0 < x < pi/2

5 0
2 years ago
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NEED HELP DUE TODAYY!!!
svetoff [14.1K]

Answer:

144

Step-by-step explanation:

5x + 4x = 7x + 32

9x = 7x + 32

2x = 32

x = 16

7(16) + 32 = 144

I think this is correct

pls mark brainliest if good

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Step-by-step explanation:

f(x)=2x+1 and g(x)=x²-7

(f/g)(x) = (2x+1)/(x²-7)

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What’s the answer to 8-(-4)
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Answer:

+ 12

Step-by-step explanation:

8 - (- 4) = 8 + 4 = 12

8 0
3 years ago
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