Hello!
**Process pictured below**
When dividing, find how many times the first time in the divisor (2x + 3) fits into the first time of the dividend (2x³ + 5x² - 3x - 5). In this step, it fits x² times.
Multiply x² by the terms in the divisor and subtract from the dividend. Bring down the next term in the dividend to continue the process.
Repeat this step until you reach the last number. In this case, there was a remainder of 4. In order to write the remainder, you must express it over the divisor which makes it 4 / 2x + 3.
The quadratic equation in its generic form is:
ax2 + bx + c
To complete squares we must add the following term:
(b / 2) ^ 2
The equation is:
ax2 + bx + c + (b / 2) ^ 2
We have the following equation:
x ^ 2 - 5x + k = 7
By completing squares we have:
x ^ 2 - 5x + (-5/2) ^ 2 = 7 + (-5/2) ^ 2
Rewriting:
x ^ 2 - 5x + 6.25 = 7 + 6.25
Answer:
A constant term should be used to complete the square is:
6.25
Step-by-step explanation:
17². + 144²=x²
289 + 20736=x²
x²=21025
x =√21025
x=145
145 miles apart
I'm not sure where it starts and ends
Answer:
the equation is y = ax + b (a ≠ 0)
see in the graph, the line passed through (0;3) and (1;5)
=>b = 3
a + b = 5
<=> a = 2
b = 3
=> the equation is y = 2x + 3
Step-by-step explanation:
