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Bogdan [553]
3 years ago
14

Whats is the solution for the system ? Help me

Mathematics
1 answer:
Yanka [14]3 years ago
3 0

Answer:

(4,3)

Step-by-step explanation:

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A blender was originally sold for $90 and has been marked
ale4655 [162]

Answer:

88%

Step-by-step explanation:

From the question given above, the following data were obtained:

Original amount = $ 90

Discounted amount = $ 79.20

Percentage of discount =?

Let the percentage of discount be y %

Thus, we can obtain the value of y as follow:

y /100 × 90 = 79.20

90y /100 = 79.20

Cross multiply

90y = 100 × 79.20

90y = 7920

Divide both side by 90

y = 7920/90

y = 88

Thus, the percentage discount of the blender is 88%

5 0
3 years ago
Read 2 more answers
Use elimination to solve the system of equations:
tatyana61 [14]
<span><span><span><span>2x</span>+<span>3y</span></span>=1</span>;<span><span>x+<span>4y</span></span>=<span>−2

</span></span></span>Steps:

<span>Multiply the second equation by -2, then add the equations together.

</span><span>(<span><span><span>2x</span>+<span>3y</span></span>=1</span>)

</span><span><span>−2</span><span>(<span><span>x+<span>4y</span></span>=<span>−2</span></span>)

</span></span>Becomes:

<span><span><span>2x</span>+<span>3y</span></span>=1

</span><span><span><span>−<span>2x</span></span>−<span>8y</span></span>=4

</span>Add these equations to eliminate x:

<span><span>−<span>5y</span></span>=5

</span>Then solve<span><span>−<span>5y</span></span>=5</span>for y:

<span><span><span>−<span>5y</span></span><span>−5</span></span>=<span>5<span>−5</span></span></span>(Divide both sides by -5)

<span>y=<span>−1

</span></span>Now that we've found y let's plug it back in to solve for x.

Write down an original equation:

<span><span><span>2x</span>+<span>3y</span></span>=1

</span>Substitute<span>−1</span>foryin<span><span><span><span>2x</span>+<span>3y</span></span>=1</span>:

</span><span><span><span>2x</span>+<span><span>(3)</span><span>(<span>−1</span>)</span></span></span>=1

</span><span><span><span>2x</span>−3</span>=1</span>(Simplify both sides of the equation)

<span><span><span><span>2x</span>−3</span>+3</span>=<span>1+3</span></span>(Add 3 to both sides)

<span><span>2x</span>=4

</span><span><span><span>2x</span>2</span>=<span>42</span></span>(Divide both sides by 2)

<span>x=2

</span>Answer:

<span><span>x=<span><span>2<span> and </span></span>y</span></span>=<span>−<span>1

</span></span></span>
7 0
3 years ago
| 2p -1 | =45, what are the values of p?
Alex73 [517]

Answer:

p = 23       and p = -22

Step-by-step explanation:

| 2p -1 | =45

Absolute value equations have 2 solutions, one positive value and one negative

2p-1 = 45    and 2p-1 = -45

Add 1 to all sides

2p-1+1 = 45+1    and 2p-1+1 = -45+1

2p = 46                        2p = -44

Divide by 2

2p/2 = 46/2    and   2p/2  = -44/2

p = 23       and p = -22

5 0
3 years ago
Read 2 more answers
If (1,0) is an ordered pair of the function f(x), which of the following is an ordered pair of the inverse of f(x)?
Flauer [41]

Answer:

A. (0,1)

Step-by-step explanation:

all you do is switch the X and Y coordinates  

5 0
3 years ago
Simplify the expression. Assume that all variables represent nonzero real numbers.StartFraction (4 n Superscript 4 Baseline q Su
Alja [10]

Answer:

\frac{ - 3}{ 256  {q}^{10} {n}^{8}  }

Step by step explanation:

\frac{ {(4 {n}^{4} {q}^{5})}^{2}  {(8 {n}^{4} q)}^{-2} }{  {(- 3 {nq}^{9})}^{ - 1}   {(4 {n}^{3} {q}^{9})  }^{3} }

first we will change the terms with negative superscrips to the other side of the fraction

\frac{{(4 {n}^{4} {q}^{5})}^{2}{(- 3 {nq}^{9})}^{ 1}}{{(4 {n}^{3} {q}^{9})}^{3} {(8 {n}^{4} q)}^{2} }

then we will distribute the superscripts

\frac{ {4}^{2} {n}^{2 \times 4} {q}^{2 \times 5} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{3 \times 3} {q}^{9 \times 3} {8 }^{2}{n}^{4 \times 2}  {q}^{2} }

\frac{ {4}^{2} {n}^{8} {q}^{10} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{9} {q}^{27} {8 }^{2}{n}^{8}  {q}^{2} }

as when multiplying two powers that have the same base, we can add the exponents and, to divide podes with the same base, we can subtract the exponents

{4}^{2 - 3}  {q}^{10  + 9 - 2 - 27}  {n}^{8 + 1 - 8 - 9}  {8}^{ - 2}  { (- 3)}^{1}

{4}^{ - 1}  {q}^{ - 10}  {n}^{ - 8}  {8}^{ - 2}  { (- 3)}^{1}

then we will change again the terms with negative superscrips to the other side of the fraction

\frac{ - 3}{ 4 \times  {8}^{2}  {q}^{10} {n}^{8}  }

\frac{ - 3}{ 256  {q}^{10} {n}^{8}  }

4 0
3 years ago
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