Answer:
-52
Step-by-step explanation:
-18+6=-12
-12-40=-52
Answer:
Except k=7, any real number for k would cause the system of equations to have no solution.
Step-by-step explanation:
In general a system of equations can be represented as ax+by=c and dx+ey=f. In order this system of equations to have NO SOLUTIONS a/d=b/a≠c/f. In our example a=6, b=4, c=14, d=3, e=2 and f=k. To apply the formula above, 6/3=4/2≠14/k. Hence k≠7. It can be concluded that except k=7, any real number for k would cause the system of equations to have no solutions.
Just for information, if k=7 the system will have infinitely many solutions.
The discontinuity are the point wherein the function is not defined.
The zeros are the points wherein f(x)=0.
Computing the discontinuity points:
Set

then the discontinuity point is at

.
Comptine the zeroes:
Set

Compute the discriminant:

Then with quadratic formula we get the solutions:

The two zeros are
Answer: 32x-68
Step-by-step explanation:
(f•g) is equal to f(gx)
f(x)=4(2x-5)+3
Which is 8x-20+3=8x-17
Now multiply by 4.
4(8x-17)
= 32x-68
First plug in (x+h) for x in the function.
f(x+h)= 2(x-h)^2-3(x-h) = 2(x^2-2xh+h^2)-3x-3h =
2x^2-4xh+2h^2-3x-3h - 2x^2 +3x =
(-4xh +2h^2-3h)/h
-4x +2h-3