The sum of 2 sides of a triangle needs to be greater than the length of the 3rd side.
14 + 29 = 43 (this is greater than 41)
14 + 41 = 55 (this is greater than 29)
29 + 41 = 70 (this is greater than 14)
(14, 29,41) can form a triangle.
In each case, you can use the second equation to create an expression for y that will substitute into the first equation. Then you can write the result in standard form and use any of several means to find the number of solutions.
System A
x² + (-x/2)² = 17
x² = 17/(5/4) = 13.6
x = ±√13.6 . . . . 2 real solutions
System B
-6x +5 = x² -7x +10
x² -x +5 = 0
The discriminant is ...
D = (-1)²-4(1)(5) = -20 . . . . 0 real solutions
System C
y = 8x +17 = -2x² +9
2x² +8x +8 = 0
2(x+2)² = 0
x = -2 . . . . 1 real solution
Answer:
26
Step-by-step explanation:
Use the Pythagorean Theorem: 
Wouldn't it be B ??? Hope this is right:) can you take a look at mine??
Answer:
is the equation of this parabola.
Step-by-step explanation:
Let us consider the equation
![\mathrm{Range\:of\:}-4x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:0]\end{bmatrix}](https://tex.z-dn.net/?f=%5Cmathrm%7BRange%5C%3Aof%5C%3A%7D-4x%5E2%3A%5Cquad%20%5Cbegin%7Bbmatrix%7D%5Cmathrm%7BSolution%3A%7D%5C%3A%26%5C%3Af%5Cleft%28x%5Cright%29%5Cle%20%5C%3A0%5C%3A%5C%5C%20%5C%3A%5Cmathrm%7BInterval%5C%3ANotation%3A%7D%26%5C%3A%28-%5Cinfty%20%5C%3A%2C%5C%3A0%5D%5Cend%7Bbmatrix%7D)
As
Therefore, the parabola vertex is
so,
Therefore, is the equation of this parabola. The graph is also attached.
