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Svet_ta [14]
3 years ago
11

Can anyone help me solve these please ?

Mathematics
1 answer:
Anton [14]3 years ago
4 0

Answer:

dufenschmertz evil incorporated...

Step-by-step explanation:

after hours ;)

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(08.01 MC)
Colt1911 [192]

Part A:

We see that this pair of equations has 1 solution. On a graph, the solutions of 2 (or more) lines is where the lines intersect. In this case, since these lines intersect 1 time, they have 1 solution.

Part B:

As previously mentioned, the solutions of multiple lines is where the lines intersect. In this case, since they intersect at (4,4), that is the solution.

6 0
3 years ago
A set of five distinct positive integers has a mean of $1000$ and a median of $100$. What is the largest possible integer that c
mixer [17]

Answer:

e = 4796

Step-by-step explanation:

given,

mean of five distinct positive number = 1000

median of the number = 100

100 is median means two number will be less than 100 and two number will be greater than 100.

let five number be

a , b, c, d, e

'e' should be the largest number

As 100 is median so 'c' = 100.

'a' and 'b' should be as small as possible and d should be the number nearest to 100.

As all the number are distinct so the least number be equal to 1 and 2

now d will be equal to 101 (nearest to 100)

now,

sum of the five number = 5 x 1000 = 5000

a + b + c + d + e = 5000

1 + 2 + 100 + 101 + e = 5000

e = 5000 - 204

e = 4796

hence, the largest number will be equal to e = 4796

7 0
3 years ago
Find the area of the shaded region.
MariettaO [177]

Answer:

Area of  shaded region = 134.13 square feet

Step-by-step explanation:

Area of the shaded region = Area of square - Area of circle

                                         = ( 25 \times 25) - ( \pi 12.5^2)\\= 625 - 490.87\\= 134.13 ft^2

8 0
3 years ago
I need help with this one .
skelet666 [1.2K]

Answer:

32/9

Step-by-step explanation:

2 to the fifth power is 32. 3 to the second power is 9.

3 0
3 years ago
I need help finding the angles
Lostsunrise [7]
What way are you trying to solve
6 0
3 years ago
Read 2 more answers
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