Answer:
a
The null hypothesis will be ![H_o : \mu = 60 \ kg](https://tex.z-dn.net/?f=H_o%20%3A%20%5Cmu%20%3D%2060%20%5C%20kg)
b
The alternative hypothesis will be ![H_a : \mu < 60](https://tex.z-dn.net/?f=H_a%20%3A%20%5Cmu%20%3C%20%2060)
c
The alternative hypothesis will be ![H_a : \mu > 60](https://tex.z-dn.net/?f=H_a%20%3A%20%5Cmu%20%3E%20%2060)
d
The alternative hypothesis will be ![H_a : \mu \ne 60](https://tex.z-dn.net/?f=H_a%20%3A%20%5Cmu%20%5Cne%20%20%2060)
e
left; right; both
Step-by-step explanation:
Considering question a
The body weight of the colt is ![\mu = 60 \ kg](https://tex.z-dn.net/?f=%5Cmu%20%3D%2060%20%5C%20kg)
The null hypothesis will be ![H_o : \mu = 60 \ kg](https://tex.z-dn.net/?f=H_o%20%3A%20%5Cmu%20%3D%2060%20%5C%20kg)
Considering question b
Given that we want to test the claim that the average weight of a wild Nevada colt is less than 60 kg , then
The alternative hypothesis will be ![H_a : \mu < 60](https://tex.z-dn.net/?f=H_a%20%3A%20%5Cmu%20%3C%20%2060)
Considering question c
Given that we want to test the claim that the average weight of such a wild colt is greater than 60 kg , then
The alternative hypothesis will be ![H_a : \mu > 60](https://tex.z-dn.net/?f=H_a%20%3A%20%5Cmu%20%3E%20%2060)
Considering question d
Given that we want to test the claim that the average weight of such a wild colt is different from 60 kg , then
The alternative hypothesis will be ![H_a : \mu \ne 60](https://tex.z-dn.net/?f=H_a%20%3A%20%5Cmu%20%5Cne%20%20%2060)
Considering question e
For question b , the corresponding p-value will be on the left because the average weight is less than 60 kg
For question c , the corresponding p-value will be on the right because the average weight is more than 60 kg
For question d , the corresponding p-value will be on both because the average weight is different from 60 kg