An interval graph in graphical theory is indeed an undirected graph formed by an interval set just on true line, with a top for every interval as well as an edge between vertex v to intersections. Graph intervals and these graphs are chordal graphs and graphs that are perfect, and the further discussion can be defined as follows:
Given:
![\bold{Interval \ \[-6, 3\]}](https://tex.z-dn.net/?f=%5Cbold%7BInterval%20%5C%20%5C%5B-6%2C%203%5C%5D%7D)
To find:
Domain=?
Solution:
The is a graphic over the![[-6,3]](https://tex.z-dn.net/?f=%5B-6%2C3%5D)
interval.
A<em><u> graph of the domain</u></em> ![[-3,6 ]](https://tex.z-dn.net/?f=%5B-3%2C6%20%5D)
is indicated mostly by the <em><u>transformation </u></em>that <em><u>horizontal shifts</u></em> to combat 
.
=|x-3|
Therefore, the final answer is "Option (D)".
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Answer:
At 43.2°.
Step-by-step explanation:
To find the angle we need to use the following equation:
Where:
d: is the separation of the grating
m: is the order of the maximum
λ: is the wavelength
θ: is the angle
At the first-order maximum (m=1) at 20.0 degrees we have:
Now, to produce a second-order maximum (m=2) the angle must be:
Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.
I hope it helps you!
Yes, your answer is correct.
Area of box : 18*18, which is 324
area of larger triangle : 18*16/2 which is 144
area of larger triangle : 8*16/2 which is 64
add them all to get 532
Answer:
![\textbf{$x \in (-\infty, 3] $}\\](https://tex.z-dn.net/?f=%5Ctextbf%7B%24x%20%5Cin%20%28-%5Cinfty%2C%203%5D%20%24%7D%5C%5C)
Step-by-step explanation:
![\textup{Given:}\\$ 4x + 6 $\textup{Subtracting $6$ from both the sides }\\$ 4x \leq 18 - 6 \hspace{5mm} (=12) $\\\textup{Dividing by $4$ on both the sides: \hspace{15mm} [Note that the sign of the inequality changes only when we divide it by a negative number]}\\$$ x \leq 3 $$\\\textup{$x$ can be any real number less than or equal to 3.}\\$ \iff x \in R^- \cup \{a : 0 \leq a \leq 3\} $](https://tex.z-dn.net/?f=%5Ctextup%7BGiven%3A%7D%5C%5C%24%204x%20%2B%206%20%24%5Ctextup%7BSubtracting%20%246%24%20from%20both%20the%20sides%20%7D%5C%5C%24%204x%20%5Cleq%2018%20-%206%20%5Chspace%7B5mm%7D%20%28%3D12%29%20%24%5C%5C%5Ctextup%7BDividing%20by%20%244%24%20on%20both%20the%20sides%3A%20%5Chspace%7B15mm%7D%20%5BNote%20that%20the%20sign%20of%20the%20inequality%20changes%20only%20when%20we%20divide%20it%20by%20a%20negative%20number%5D%7D%5C%5C%24%24%20x%20%5Cleq%203%20%24%24%5C%5C%5Ctextup%7B%24x%24%20can%20be%20any%20real%20number%20less%20than%20or%20equal%20to%203.%7D%5C%5C%24%20%5Ciff%20x%20%5Cin%20R%5E-%20%5Ccup%20%5C%7Ba%20%3A%200%20%5Cleq%20a%20%5Cleq%203%5C%7D%20%24)
