2×2=4
4÷2=2
4+2=6
4+2+6=12
we know that,
put a number you like anything I will write x°
x°+12°=90°
90°-12°=78°,,
again,
78°-12°=66°,,
now,
remove 6° from 60°
60
-----
12
=5,,
In f(x) = 3x + 2, the x is being represented in the function. So, if we replace the x with the g(x) functions, we get:
f(g(x)) = 3(2x - 4) + 2
f(g(x)) = 6x - 12 + 2
f(g(x)) = 6x - 10
Answer:
The correct options are: Interquartile ranges are not significantly impacted by outliers. Lower and upper quartiles are needed to find the interquartile range. The data values should be listed in order before trying to find the interquartile range. The option Subtract the lowest and highest values to find the interquartile range is incorrect because the difference between lowest and highest values will give us range. The option A small interquartile range means the data is spread far away from the median is incorrect because a small interquartile means data is nor spread far away from the median
Answer:
<h3>
</h3>
Step-by-step explanation:
Distribute 3 through the parentheses
Distribute 2 through the parentheses
⇒
Collect like terms
⇒
Hope I helped!
Best regards!!
Yes I’m sure you know what
