Solution:
<u>Simplify the equation and solve for r.</u>
- r/16 + 6 = 7
- => r/16 = 7 - 6
- => r/16 = 1
- => r = 16
The value of r is 16.
<u>Check:</u>
- r/16 + 6 = 7
- => 16/16 + 6 = 7
- => 1 + 6 = 7
- => 7 = 7 (Proved correct)
Answer:
answer un known
Step-by-step explanation:
u divide
Answer:
happy birthday
Step-by-step explanation:
thank you
Answer:
Some of the products do not show the correct powers of x.
Step-by-step explanation:
From the picture,
3x(2x - 1) = 6x² - 3x
The correct display on the tile should look like this :
_____+x ______ +x ______ +x
+x __ +x² ______+x² ______+x²
|
+x__ +x² ______ +x² ______+x²
|
- ___ -x _______ -x _______-x
+6x² - 3x
Answer:
(-2, 3)
Step-by-step explanation:
4x + 5y = 7
3x - 2y = -12
Let's solve this by elimination. We want to eliminate one variable at a time. This means we need to multiply the equations to create a common multiple to cancel out a variable.
Let's work with y.
5y and -2y: For these values to cancel out, we need to multiply each term to create a common multiple.
2(4x + 5y = 7)
5(3x - 2y = -12)
Multiply.
8x + 10y = 14
15x - 10y = -60
Eliminate.
23x = -46
Divide both sides by 23.
x = -2
Now that we know x, let's plug it back into one of equations to find y.
4x + 5y = 7
4(-2) + 5y = 7
Multiply.
-8 + 5y = 7
Add.
5y = 15
Divide.
y = 3
Now we know x and y; let's plug both back into the equation we have not checked yet.
3x - 2y = -12
3(-2) - 2(3) = -12
Multiply.
-6 - 6 = -12
Subtract.
-12 = -12
Your solution is correct.
(-2, 3)
Hope this helps!
