Find 6m if m = 5/13 6 5/13 5 2 4/12 5/78

xz_007 [3.2K]

Answer:

It is +2 or since (+2)*(+2 ) gives. If you think that it would be (-2) also then you are wrong because root of a positive rational number is always positive number.

Step-by-step explanation:

Let the square root of four be ‘k’.

Then we have

(4)^1/2=k

(Squaring both sides)

4=(k)^2

=>(k)^2–4=0

=>(k)^2-(2)^2=0

=>[k+2][k-2]=0 {since (a)^2-(b)^2=(a+b)(a-b)}

if product of two numbers is 0 then either of one must be zero.

If k+2=0 then k=-2

If k-2=0 then k=2

From here we got two answers but -2 should be omitted because when we square an equation we add “root extra”which means that when we square an equation one root is added.

3 0

2 years ago

URGENT: If θ is a second-quadrant angle and cosθ = -2/3, then tanθ = _____.

dangina [55]

In the second quadrant, both cos and tan are negative while only sin is positive.

To find tan, we will use the following property below:

$\large \boxed{ {tan}^{2} \theta = {sec}^{2} \theta - 1}$

Sec is the reciprocal of cos. If cos is a/b then sec is b/a. Since cos is 2/3 then sec is 3/2

$\large{ {tan}^{2} \theta = {( - \frac{3}{2}) }^{2} - 1} \\ \large{ {tan}^{2} \theta = \frac{9}{4} - 1} \\ \large{ {tan}^{2} \theta = \frac{9}{4} - \frac{4}{4} \longrightarrow \frac{5}{4} } \\ \large{tan \theta = \frac{ \sqrt{5} }{ \sqrt{4} } } \\ \large \boxed{tan \theta = \frac{ \sqrt{5} }{2} }$