X=27 and y=11
if you let each number equal x and y we know the sum is 38 so x+y=38
and the smaller is 16 less than the larger
. so if we say the smaller number is 7 then x-16=y
these can be solved as a simultaneous equation. x+(x-16)=38
2x-16=38
2x=54
x=27
(27)-16=y
y=11
so the answer is x=27 y=11
Answer:
B.
Step-by-step explanation:
First, let's start from the parent function. The parent function is:

The possible transformations are so:
,
where a is the vertical stretch, b is the horizontal stretch, c is the horizontal shift and d is the vertical shift.
From the given equation, we can see that a=1 (so no change), b=3, c=-3 (<em>negative </em>3), and d=3.
Thus, this is a horizontal stretch by a factor of 3, a shift of 3 to the <em>left </em>(because it's negative), and a vertical shift of 3 upwards (because it's positive).
Answer:
2
Step-by-step explanation:
|-6+8|
Add/subtract the numbers: -6 + 8 = 2
= |2|
Apply the absolute value rule: |a| = a, a ≥ 0
= 2
I believe there are 3 short haired kittens, but let me know if I am wrong.
Answer:
52
Step-by-step explanation:
sorry if it's wrong