Answer:
Answer
sqrt(108)
6 sqrt(3)
10.3923
I don't know which answer you want.
Step-by-step explanation:
- Drop a perpendicular from the top angle to the base.
- The base is cut into 2 equal parts.
- Each part is 12/2 = 6
- The perpendicular, as its name implies, meets the base at 90o.
- You can use the Pythagorean Theorem to find the height.
h^2 = side^2 - (1/2 b)^2
h^2 = 12^2 - 6^2
h^2 = 144 - 36
h^2 = 108
Take the square root of both sides
h = sqrt(108)
h = sqrt(2*2 * 3 * 3 * 3)
h = 2 * 3 sqrt(3)
h = 6sqrt(3)
h = 6 * 1.7321
h = 10.3923
Answer:
Step-by-step explanation:
Sum a with a-s ;b with b-s so:
0.75a + 10b + a – 2b=0.75a+a+10b-2b=1.75a+8b
The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is
(x - x^2)^2 * sqrt(3)/4.
Integrating from x = 0 to x = 1, we have
[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4
= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144.
Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...
