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2 years ago

Hi im sorry to ask for help but im really stressed about this.please help ill do anything

Mathematics

1 answer:

Delvig [45]2 years ago

4 0

Answer:

b . 5×4 = 20

hope it helps :) , plz check them all yourself again ^^

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The digit 3 in which number represents a value of 3 tens ?

Korvikt [17]

Answer:

Step-by-step explanation:

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2 years ago

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Solve for x please and thank you

Sphinxa [80]

9514 1404 393

Answer:

x = 7

Step-by-step explanation:

The product of segment lengths is the same for the two chords.

9(21) = x(27)

x = 189/27 . . . . . divide by 27

x = 7

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2 years ago

Is square root 1 minus sine squared theta = cos Θ true? If so, in which quadrants does angle Θ terminate?

Cloud [144]

Answer:

True; quadrants I & IV

Step-by-step explanation:

We know the relation between sine and cosine function which is given by

$\sin^2 \theta +\cos^2 \theta = 1$

Let us solve this equation for cosine function.

$\cos^2 \theta = 1-\sin^2 \theta$

Take square root both sides. When ever we take square root we need to write the solution in plus minus form

$\sqrt{\cos^2 \theta}=\pm\sqrt{1-\sin^2 \theta}$

$\cos \theta=\pm\sqrt{1-\sin^2 \theta}$

$\cos \theta=-\sqrt{1-\sin^2 \theta}, \sqrt{1-\sin^2 \theta}$

If Θ is in quadrants I and IV then the value will be positive and if Θ is in II and III quadrant then the value is negative.

Hence, if Θ is in quadrants I & IV, then we have

$\cos \theta=\sqrt{1-\sin^2 \theta}$

Thus, the correct option is: True; quadrants I & IV

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2 years ago

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I’ll give brainliest if correct!

zysi [14]

Answer:

D or it does represent with the equation of y=3x

Step-by-step explanation:

8 0

2 years ago

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If someone has 6 3/4 cups of batter and needs 12 cups total how much more batter does he/she need?

Slav-nsk [51]

They need 5 1/4 cups of batter. Because 6 3/4 + 5 1/4 = 12. Hope this helped :P

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2 years ago

Hi im sorry to ask for help but im really stressed about this.please help ill do anything ​

Hi im sorry to ask for help but im really stressed about this.please help ill do anything