Question 9
Given the segment XY with the endpoints X and Y
Given that the ray NM is the segment bisector XY
so
NM divides the segment XY into two equal parts
XM = MY
given
XM = 3x+1
MY = 8x-24
so substituting XM = 3x+1 and MY = 8x-24 in the equation
XM = MY
3x+1 = 8x-24
8x-3x = 1+24
5x = 25
divide both sides by 5
5x/5 = 25/5
x = 5
so the value of x = 5
As the length of the segment XY is:
Length of segment XY = XM + MY
= 3x+1 + 8x-24
= 11x - 23
substituting x = 5
= 11(5) - 23
= 55 - 23
= 32
Therefore,
The length of the segment = 32 units
Question 10)
Given the segment XY with the endpoints X and Y
Given that the line n is the segment bisector XY
so
The line divides the segment XY into two equal parts at M
XM = MY
given
XM = 5x+8
MY = 9x+12
so substituting XM = 5x+8 and MY = 9x+12 in the equation
XM = MY
5x+8 = 9x+12
9x-5x = 8-12
4x = -4
divide both sides by 4
4x/4 = -4/4
x = -1
so the value of x = -1
As the length of the segment XY is:
Length of segment XY = XM + MY
= 5x+8 + 9x+12
= 14x + 20
substituting x = 1
= 14(-1) + 20
= -14+20
= 6
Therefore,
The length of the segment XY = 6 units
P(red) first drawn:
20/36=5/9
P(red) second drawn:
19/35
95/315 or 19/63. As a result, the probability that both marbles are red is 19/63. Hope it help!
Answer:
56 eggs
Step-by-step explanation:
If 
of all eggs are green, 
of all are blue, then
of all eggs are red.
We know that there are 26 red eggs
![26\text{ eggs }-\dfrac{13}{28}\\ \\x\text{ eggs }- 1[=\dfrac{28}{28}]](https://tex.z-dn.net/?f=26%5Ctext%7B%20eggs%20%7D-%5Cdfrac%7B13%7D%7B28%7D%5C%5C%20%5C%5Cx%5Ctext%7B%20eggs%20%7D-%201%5B%3D%5Cdfrac%7B28%7D%7B28%7D%5D)
Make a proportion
![\dfrac{26}{x}=\dfrac{\frac{13}{28}}{1}\\ \\26\cdot 1=x\cdot \dfrac{13}{28}\ [\text{Cross multiply}]\\ \\13x=26\cdot 28\ [\text{Multiply by 28 to get rid of fraction}]\\ \\x=\dfrac{26\cdot 28}{13}\ [\text{Divide by 13 to get x}]\\ \\x=2\cdot 28\\ \\x=56](https://tex.z-dn.net/?f=%5Cdfrac%7B26%7D%7Bx%7D%3D%5Cdfrac%7B%5Cfrac%7B13%7D%7B28%7D%7D%7B1%7D%5C%5C%20%5C%5C26%5Ccdot%201%3Dx%5Ccdot%20%5Cdfrac%7B13%7D%7B28%7D%5C%20%5B%5Ctext%7BCross%20multiply%7D%5D%5C%5C%20%5C%5C13x%3D26%5Ccdot%2028%5C%20%5B%5Ctext%7BMultiply%20by%2028%20to%20get%20rid%20of%20fraction%7D%5D%5C%5C%20%5C%5Cx%3D%5Cdfrac%7B26%5Ccdot%2028%7D%7B13%7D%5C%20%5B%5Ctext%7BDivide%20by%2013%20to%20get%20x%7D%5D%5C%5C%20%5C%5Cx%3D2%5Ccdot%2028%5C%5C%20%5C%5Cx%3D56)
Answer:
just follow the rules
Step-by-step explanation:
Cramer's rule applies to the case where the coefficient determinant is nonzero. ... A simple example where all determinants vanish (equal zero) but the system is still incompatible is the 3×3 system x+y+z=1, x+y+z=2, x+y+z=3.
Write the system as a matrix equation. ...
Create the inverse of the coefficient matrix out of the matrix equation. ...
Multiply the inverse of the coefficient matrix in the front on both sides of the equation. ...
Cancel the matrix on the left and multiply the matrices on the right.
