The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
Answer:
The value of x is 5.
The value of y is 4.
Step-by-step explanation:
From the figure, the lengths of the lines with equal number of markings are equal.
So, we will have the length of 7x - 4 = 31.
We solve for 'x'.
We get: 7x = 35
⇒ x = 5
Similarly, 4y + 8 = 24
⇒ 4y = 24 - 8
⇒ 4y = 16
⇒ y = 4
Therefore, the value of x = 5 and y = 4.
Hence, the answer.
This is the same as any math problem you may have solved before.
First, start by isolating the x on one side. I will choose to keep the coefficient positive, so I will add x to both sides.
6>2x+2
Subtract 2
4>2x
Divide by 2
2>x
Or
x<2
Answer:
64?
Step-by-step explanation:
3/5= 40
40:5=8
8 x 3=24
24 x 40=64
dunno if it's really correct so....
