To solve this, you need to isolate/get the variable "u" by itself in the inequality: u = unknown number
2u - 3 < 1 Add 3 on both sides
2u - 3 + 3 < 1 + 3
2u < 4 Divide 2 on both sides to get "u" by itself
u < 2 (u is any number less than 2)
When the inequality sign is >/< (greater than/less than), the dot/endpoint is an open/unfilled circle.
When the inequality sign is ≥/≤ (greater than or equal to/less than or equal to), the dot is a closed/filled circle.
u < 2
Start making a ray by placing an open circle on 2(click on the dot/endpoint to change it to be open if it isn't already), then have the ray point left where the numbers would be decreasing because "u" is any number less than 2. If you can place the end of the ray at the end of the number line.
The correct answer would be the 2nd option because it increases by a specific amount every X value.
Answer:
17 is the answers to the question
