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olga2289 [7]
2 years ago
9

What is the total number of servings the modified recipe will make?

Mathematics
2 answers:
Digiron [165]2 years ago
5 0

9514 1404 393

Answer:

  B.  4

Step-by-step explanation:

Equating exponents, we have ...

  2x +7 = 15

  2x = 8 . . . . . subtract 7

  x = 4 . . . . . . divide by 2

The equation is true when the value of x is 4.

oksano4ka [1.4K]2 years ago
3 0

hope this helps enjoy.

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How are geometric sequences similar to arithmetic sequences? How are they different?
ollegr [7]
The differences between arithmetic and geometric sequences is that arithmetic sequences follow terms by adding, while geometric sequences follow terms by multiplying. The similarities between arithmetic and geometric sequences is that they both follow a certain term pattern that can't be broken. There you go
3 0
3 years ago
An object launched straight up at a speed of 29.4 meters per second has a height, h, in meters of h , t seconds after the object
Nostrana [21]

Answer:

h = 44.06 meters (maximum height)

the time the object takes to complete this whole path is 6 seconds, this is why the time at which the object reaches its maximum height will between 0 and 6 seconds

Step-by-step explanation:

To solve this question, we need to first recognize that this is a constant acceleration problem, specifically, it can be thought of as a projectile motion problem.

Recall, the equations of motion:

1) v^2 - v_0^2 = 2a(s - s_0)\\2) s = v_0^2  + \frac{1}{2} at^2\\3) v = v_0 + at

What do we already know?

  • v_0 = 29.4 ms^-1
  • The launch is straight up
  • a = -9.81 ms^-2 this is the gravitational acceleration g
  • s_0 = 0 m, since our reference point is at s = 0, (the ground)

We can use use the Eq(1):

we know that when any object is launched up, at maximum height its velocity is going to be zero, v = 0 ms^-2

v^2 - v_0^2 = 2a(s - s_0)\\0^2 - (29.4)^2 = 2(-9.81)(s- 0)\\s = 44.06 m

this is the maximum height!

Why does t have to between zero and six?

We can answer this using a bit visualization, if you think about the second equation

s = v_0 t - \frac{1}{2}at^2\\ s = 29.4t - 4.905t^2

this is the equation of the whole trajectory that object makes.

and if you solve this by making s = 0, you will get the times at which the object was at the ground. the times will be 0s and 5.99s.

so the amount of time the object takes to go through this whole path is 6 seconds and this why the object will only reach its maximum height in between this time interval.

hope this helps :)

5 0
3 years ago
A plank of wood is 220 cm long.I cut it in 14cm pieces. what lenght of wood i will have left over?
Nana76 [90]

The required Length is 10cm.

What is length?

  • Length is a measure of distance. In the International System of Amounts, length is a volume with dimension distance. In utmost systems of dimension a base unit for length is chosen, from which all other units are deduced.
  • Length is generally understood to mean the most extended dimension of a fixed object. still, this isn't always the case and may depend on the position the object is in.
  • Varied terms for the length of a fixed object are used, and these include height, which is the perpendicular length or perpendicular extent, and range, breadth, or depth. Height is used when there's a base from which perpendicular measures can be taken. range or breadth generally relates to a shorter dimension when the length is the longest one.

220 / 14 gives us 15.

You have to understand that this means 15 whole 14 cm pieces and a Length of 1 piece.

thus 14 * 15 = 210

So 220- 210 = 10

where you know 220- 210 is< 15

Hence, The correct Length is 10cm.

Learn more about Length here:

brainly.com/question/2217700

#SPJ9

7 0
1 year ago
Share 1200kg in the ratio 3:37
bearhunter [10]

Answer:

3+37=40

3/40×1200=90kg

37÷40×1200=1110kg

Step-by-step explanation:

''.''

5 0
2 years ago
Read 2 more answers
Elena and Jorge have similar problems and find the same answer. Each determines that the solution to e problem is 24.
Colt1911 [192]

What is the question??

6 0
3 years ago
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