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kherson [118]
2 years ago
5

Help please: Rewrite the problem in terms of some using the double-angle formula.

Mathematics
1 answer:
Pie2 years ago
4 0

sin(2\theta)=2sin(\theta)cos(\theta) \\\\[-0.35em] ~\dotfill\\\\ sin(x)cos(x)=\cfrac{\sqrt{3}}{4}\implies \stackrel{\textit{multiplying both sides by 2}}{2sin(x)cos(x)=2\left( \cfrac{\sqrt{3}}{4} \right)}\implies sin(2x)=\cfrac{\sqrt{3}}{2}

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HURRY PLEAASEEE. 2x2 – 13x + 24 = 3
Katena32 [7]

Answer:

7/2 and 3

Step-by-step explanation:

using quadratic formula

{-(-13) +- √(-13)^2 - 4(2)(21) } /2(2)

-(-13)+1 / 4 = 7/2

-(-13)-1 / 4 = 3

5 0
3 years ago
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Write the fraction 3 15/25 as a decimal and percent
Allushta [10]

Answer

Decimal is 3.6

Percent is 360%

Step-by-step explanation:

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3 years ago
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D=domain and the domain is 0
Temka [501]
What specifically do you need help with? range is the y-values and domain is the x-values. so if you write down each point you’ll have domain and range.... comment what else i can help with?
4 0
3 years ago
To help divide a group into 4 teams, the teacher brought out a bag with equal numbers of 4 different colored popsicle sticks (gr
NeX [460]
The set of all possible events Ω

Ω = 24 ( 4*7 = 28 stick)

<span>set of events favorable A
A = 7 ( </span><span>sticks of green is 7)

</span><span>Probability P
P(A) = A/</span>Ω = 7/28 = 1/4 = 0,25

Answer A
<span>The first person has the ability to draw seven green sticks of twenty-four </span>
3 0
3 years ago
A pole that is 3m tall casts a shadow that is 1.22m long. At the same time, a nearby building casts a shadow that is 38.5m long.
vichka [17]
Refer to the diagram shown below.

The height of the pole is CD (3 m), and its shadow is AB (1.22 m).
The height of the building is h m, and its shadow is AD (38.5 m).

The two triangles ΔABC and ΔADE are similar because of AAA.
Therefore
\frac{DE}{BC} = \frac{AD}{AB} \\\\  \frac{h}{3} = \frac{38.5}{1.22}

Cross multiply.
1.22 h = 3*38.5 = 115.5
h = 115.5/1.22 = 140.91 m

Answer: 141 m (nearest meter)

5 0
4 years ago
Read 2 more answers
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