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2 years ago

Find the area of the shaded part of the triangle below. Round to the nearest tenth if needed.

Mathematics

2 answers:

konstantin123 [22]2 years ago

7 0

Answer:

212.5

Step-by-step explanation:

For triangles, A = (bh)/2

You can do 15+25 to find the base, which is 40. From here do 17*40/2. You get 340. However, you need to remove the right triangle on the left side.

Again do 17*15/2, which you get 127.5.

From here subtract 127.5 from 340 and get 212.5

vaieri [72.5K]2 years ago

4 0

Answer:

Step-by-step explanation:

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MariettaO [177]

Answer:

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1 year ago

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#20 I’m not sure how to solve it. And the answer should be able to grid in like on the SAT

r-ruslan [8.4K]

Answer:

Step-by-step explanation:

i (a + bi) = 1

ai + b(-1) = 1

ai − b = 1

Match the coefficients.

ai = 0

-b = 1

Therefore, a = 0 and b = -1.

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2 years ago

How to solve 6h-3.3h

LiRa [457]

Answer:

2.7h

Step-by-step explanation:

The variable "h" does not matter. Leave the "h" like it is, and just subtract.

Hope it helps! Leave a comment if you have questions!

3 0

3 years ago

A circle has a radius of \blue{3}3start color #6495ed, 3, end color #6495ed. An arc in this circle has a central angle of 340^\c

shusha [124]

Answer:

length of arc ≈ 17.8 (to the nearest tenth)

Step-by-step explanation:

To find the length of the arc we use the formula for finding length of an arc.

length of arc = ∅/360 × 2πr

where

∅ = central angle

r = radius

∅ = 340°

r = 3

length of arc = ∅/360 × 2πr

length of arc = 340/360 × 2 × π × 3

length of arc = 340/360 × 6π

length of arc = 2040π/360

length of arc = 204π/36

length of arc = (204 × 3.14)/36

length of arc = 640.56/36

length of arc = 17.7933333

length of arc ≈ 17.8 (to the nearest tenth)

7 0

2 years ago

Simple random sampling uses a sample of size n from a population of size N to obtain data that can be used to make inferences ab

OLEGan [10]

Answer: 6,77,040 different random samples of four accounts are possible.

Step-by-step explanation:

We have to calculate the different random samples of four accounts are possible from the population of 65 bank accounts.

we are using combination formula for calculating various combination of four accounts:

= $^{n}C_{r}$

Where,

n - total population of bank accounts

r - random samples drawn from the population

= $^{65}C_{4}$

= $\frac{n!}{r!(n-r)!}$

= $\frac{65!}{4!(65-4)!}$

= $\frac{65!}{4!(61)!}$

= 6,77,040 different random samples of four accounts are possible.

5 0

2 years ago