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Angelina_Jolie [31]
2 years ago
7

Please help me with this asap

Mathematics
1 answer:
den301095 [7]2 years ago
8 0

Answer:

76

Step-by-step explanation:

I rewrote the question so I wouldn't have to keep going back to the picture.

A poll asked 1000 adults who own smartphones where they put their smartphone while sleeping. The following two-way table of relative frequencies shows the data collected on age and smartphone habits. Of the adults polled, 200 were 65 or older.

How many of the adults polled that were 65 or older sleep with their smartphone within reach?

---------------------------------------------------------------------------------

I bet if I called this a two- way table of "percentages, written as decimals", it would make more sense.

Total number of adults 65 and older = 200. The 0.38 of them that sleep with their phone in reach = 38% of them. Multiply 200 x 0.38 = 76

To check the math, 200 x 0.62 = 124, and 124 + 76 = 200.

As always, please let me know if you have questions. I've answered each of your open questions as of now (11am CDT, USA)

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GIVING BRAINLIST ANYONE WHO CAN SOLVE ANY OF THEM!!!!
nekit [7.7K]

Answer:

x=36

x=127

x=36

5 0
3 years ago
Read 2 more answers
Consider a population of Pacific tree frogs (Pseudacris regilla). In this population of frogs, a single locus controls the produ
zloy xaker [14]

Answer:

Step-by-step explanation:

Hello!

Use these data to calculate the chi-square statistic. Report your calculated chi-square statistic to two decimal places.

In this example, the study variable is X: genotype of a single locus two allele gene that codes the mating call of tree frogs. Categorized: S₁S₁, S₁S₂, and S₂S₂.

Usually, when you have a sample of observed genotypes of a gene of interest, the goal is to check if these genotypes follow a theoretical model such as the frequency models proposed by Mendel.

In Mendelian genetics, when two heterozygous individuals (Aa, Aa) from the F1 generation are crossed, you expect the next generation (F2) to show the genotypic ratio 1:2:1 ⇒ This model means that out of 4 descendants 1 will have the genotype AA, 2 will have the genotype Aa and 1 will have the genotype aa. Since there is no theoretical model specified I'll use the mendelian ratio 1:2:1.

If this theory applies to the population then we'll expect that the proportion of the first genotype is P(S₁S₁)= 0.25, the second P(S₁S₂)= 0.5 and the third P(S₂S₂)=0.25

To test if the observed genotypes follow the theoretical model you have to apply a Chi-Square Goodness of Fit Test.

For this test the hypotheses are:

H₀:P(S₁S₁)= 0.25; P(S₁S₂)= 0.5; P(S₂S₂)=0.25

H₁: The data is not consistent with the specified distribution.

α: 0.05

Statistic: X^2= sum(\frac{(o_i-e_i)^2}{e_i} )~X^2_{k-1}

Where:

oi: Observed frequency for the i- category

ei: Expected frequency for the i-category

k= number of categories

The rejection region for this test is one-tailed to the right. This is so because if the observed and expected values are too different (the chi-square value will be high) this will mean that the population doesn't follow the theoretical model and thus reject the null hypothesis. If the differences between what's observed and what's expected are small, this will mean that the population follows the theoretical model (and you'll obtain a small chi-square value) and you will not reject the null hypothesis.

The critical value is:

X^2_{k-1; 1 - \alpha }= X^2_{3;0.95}= 7.815

If the statistic is at least 7.815, the decision is to reject the null hypothesis.

If the statistic is less than 7.815, the decision is to not reject the null hypothesis.

Step 1 is to obtain the expected frequencies for each category:

e_i= n*P_i

e_{S_1S_1}= n * P(S_1S_1)= 1341*0.25= 335.25

e_{S_1S_2}= n * P(S_1S_2)= 1341 * 0.5= 670.5

e_{S_2S_2}= n * P(S_2S_2)= 1341*0.25= 335.25

Note: the summatory of the expected frequencies is equal to the total of observations ∑ei= n. If you have doubts about your calculations, you can add them to check it: ∑ei= 335.25 + 670.5 + 335.25= 1341

X^2= (\frac{(987-335.25)^2}{335.25} )+(\frac{(333-670.5)^2}{670.5} )+(\frac{(21-335.25)^2}{335.25} ) = 1731.50

Decision: Reject null hypothesis.

I hope this helps!

3 0
3 years ago
Domain <br>1. {×€ R | X ≠ 0}<br>2. {x + R | x≠1}​
Ivenika [448]

1) Go..

domain = ( -  \infty  \:,\: 0) \: U(0 \: ,\:  +  \infty ) \\

2) Go...

domain = ( -  \infty  \: ,\: 1)U(1 \: ,\:  +  \infty ) \\

_________________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

5 0
3 years ago
A bag contains 10 marbles. Four of them are red, three blue, two white and one yellow. A marble is drawn at random. What is the
ozzi
Probability =
(number of different successful results) / (number of all possible results) .

Number of marbles that are not blue = 7
Number of marbles in the bag = 10
Probability that one marble drawn at random is not blue = 7/10 = 70% .

7 0
3 years ago
Read 2 more answers
Which is the best estimate of each percent? 24% of 398
Bingel [31]

To find the 24% of 398, multiply 398 by 24 and divide it by 100:

398\cdot\frac{24}{100}=95.52

Among the options, the number that is closest to 95.52 is 100. It means that the correct answer is B.100.

4 0
1 year ago
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