Angle CBA is the right name because it's in between C and A
Answer:
Or:
Step-by-step explanation:
We want to write the equation of a line that passes through the points (-6, 5) and (3, -5) in point-slope form.
Point-slope form is given by:
Thus, first, we need to find the slope. We can use the slope formula:
Next, we can use either of the two given points. I'll use (-6, 5). So, let (-6, 5) be (<em>x₁, y₁</em>). Substitute:
Or, fully simplified:
Using the other point, we will acquire:
Or, simplified:
0 = 0
Simplifying
7x + -11 = 5(x + -2) + 2x + -1
Reorder the terms:
-11 + 7x = 5(x + -2) + 2x + -1
Reorder the terms:
-11 + 7x = 5(-2 + x) + 2x + -1
-11 + 7x = (-2 * 5 + x * 5) + 2x + -1
-11 + 7x = (-10 + 5x) + 2x + -1
Reorder the terms:
-11 + 7x = -10 + -1 + 5x + 2x
Combine like terms: -10 + -1 = -11
-11 + 7x = -11 + 5x + 2x
Combine like terms: 5x + 2x = 7x
-11 + 7x = -11 + 7x
Add '11' to each side of the equation.
-11 + 11 + 7x = -11 + 11 + 7x
Combine like terms: -11 + 11 = 0
0 + 7x = -11 + 11 + 7x
7x = -11 + 11 + 7x
Combine like terms: -11 + 11 = 0
7x = 0 + 7x
7x = 7x
Add '-7x' to each side of the equation.
7x + -7x = 7x + -7x
Combine like terms: 7x + -7x = 0
0 = 7x + -7x
Combine like terms: 7x + -7x = 0
0 = 0
Solving
0 = 0
Answer:
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Step-by-step explanation:
II. Triangle ABC is obtuse and III. Triangle ABC is acute, because acute is less than 180° and obtuse is between 180° and 270°
