When the base of a triangle is fixed at 2.218 millimeters, the area will be 0.1098 mm².
<h3>What will the area be?</h3>
It should be noted that the area of a triangle is calculated as:
Area of triangle = (1/2)×base×height
= (1/2) × 2.218 mm × 0.099 mm
= 1.109 mm × 0.099 mm
= 0.109791 mm²
≈ 0.1098 mm²
Therefore, the <em>area</em> is 0.1098 mm².
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The base of a triangle is fixed at 2.218 millimeters. Determine the number of
significant figures of the area of the triangle with each given height of 0.099mm.
We have been given that :-
The length of a parasite in experiment A is 
The length of a parasite in experiment B is 
Let us write the the length of the parasite in experiment A in the exponent of -3.

Clearly, the length of parasite in experiment A is greater than the length of parasite in experiment B.
The difference in the length is given by


Therefore, the length of the parasite in experiment A is
inches greater than the length of the parasite in experiment B.
I don't know if you still need help. but the answer is the first one.
Answer: There are 25 ways to select two members.
Step-by-step explanation:
Since we have given that
S={E,F,G,H,J}
Number of elements = 5
We need to select two members from S allowing the repetition.
We will use "Fundamental theorem of counting":
There are 5 choices for the first member.
There are 5 choices for the second member.
So, Number of ways would be

Hence, there are 25 ways to select two members.
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