<span> allows you to </span>do<span> repeated addition quickly and efficiently</span>
Answer:
$848
Step-by-step explanation:
Calculation for the cost of this familiy's clothing in 1991
First step is to calculate the amount that is increase per year
Increase per year= ($1000-$620)/(1995-1985)
Increase per year= 380/10
Increase per year= $38
Now let y be :38*x + $620 and let x be 6 years (1991-1985)
Second step is to calculate the cost of the clothing in 1991
y = 38*6 + 620
y=228+620
y = $848
Therefore the cost of this familiy's clothing in 1991 will be $848
Just count the notches between the two points, there are 15 notches so 15 is tour answer
<span>3y^2 • 4x^2y • 5x = (3*4*5) * (</span><span>y^2 * y) * (</span><span>x^2*x) = 60 * y^3 * x^3 = 60 (xy)^3
</span>where ((<span>y^2 * y)) adding the powers in case of multiplication
and also for this:</span><span> (<span>x^2*x)</span> </span>
