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3 years ago

Not sure if i already asked this one! Math help please :)

Mathematics

1 answer:

mars1129 [50]3 years ago

8 0

Answer:

Hello again!

Original coordinates: 5, -2

New coordinates: 0, 4

Heres a picture demonstration to find the new coordinates. How I moved 5 left and 6 up

Hope that helps!

You might be interested in

Use a measuring tape to find the circumference of five circular objects.Then measure distance across each item to find its diame

MAXImum [283]

Basically
Circumference = 2 * pie * radius
To get the radius u need to measure the circles distance. For example I measured a circular mirror and the distance was 10cm. This is the diameter. To get the radius I’ll divide by 2 because the radius is from the centre of the circle to the edge. So, 10 divided by 2 = 5cm. The radius is 5cm. Now,
Circumference = 2 * pie * r
r = 5. Pie = 3.14
Circumference = 2 * 3.14 * 5
= The answer
****pie is always 3.14
I hope you understood

4 0

3 years ago

A farmer estimates that he has 9,000 bees producing honey on his farm. The farmer becomes concerned when he realizes the populat

djverab [1.8K]

Answer:

The function f(x) = 9,000(0.95)^x represents the situation.
After 2 years, the farmer can estimate that there will be about 8,120 bees remaining.
The range values, in the context of the situation, are limited to whole number

Step-by-step explanation:

The "growth" rate is -5%, so the growth factor, the base in the exponential equation, is 1.00-5% =0.95.

Using x=2, we find the population in 2 years is expected to be about ...

f(2) = 9000·0.95^2 ≈ 8123 . . . . about 8120

Using x=4, we find the population in 4 years is expected to be about ...

f(4) = 9000·0.95^4 ≈ 7331 . . . . about 7330

Since population is whole numbers of bees, the range of the function is limited to whole numbers.

The domain of the function is numbers of years. Years can be divided into fractions as small as you want, so the domain is not limited to whole numbers.

The choices listed above are applicable to the situation described.

7 0

3 years ago

The space shuttle flight control system called PASS (Primary Avionics Software Set) uses four independent computers working in p

tigry1 [53]

Answer:

$f_X(k)=\binom{4}{k}0.003^k0.997^{4-k}$

Step-by-step explanation:

Recall that a <em>probability mass function</em> defined on a discrete random variable X is just a function that gives the probability that the random variable equals a certain value k

$f_X(k)=P(X=k)$

In this case we have the event

“The computer will ask for a roll to the left when a roll to the right is appropriate” with a probability of 0.003.

Then we have 2 possible events, either the computer is right or not.

Since we have 4 computers in parallel, the situation could be modeled with a binomial distribution and the probability mass function

$f_X(k)=\binom{4}{k}0.003^k0.997^{4-k}$

This gives the probability that k computers are wrong at the same time.

6 0

3 years ago

Need help quickly please!!!

Bad White [126]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A train leaves Philadelphia at 2:00 PM. A second train leaves the same city in the same direction at 4:00 PM. The second train t

polet [3.4K]

Answer: First train speed shall be 42 mi/hr

Second train speed shall be 84 mi/hr

Yes it is the valid answer, it gets annoying when almost everyone enters the wrong answer for a good laugh. Either way, hope this helps! Have a spectacular day.

Step-by-step explanation:

What is the 1st train's head start in miles?

Let +s+ = the speed of the 1st train in mi/hr

From 2PM to 4PM is 2 hrs

+d%5B1%5D+=+s%2A2+

---------------------

Let +d+ = distance the 2nd train travels until

it overtakes the 1st train

From 4PM to 6PM is 2 hrs

Start time when the 2nd train leaves

---------------------

Equation for 1st train:

(1) +d+-+2s+=+s%2A2+

Equation for 2nd train:

(2) +d+=+%28+s%2B42+%29%2A2+

--------------------

Substitute (2) into (1)

(1) +%28+s%2B42+%29%2A2+-+2s+=+s%2A2+

(1) +2s+%2B+84+-+2s+=+2s+

(1) +2s+=+84+

(1) +s+=+42+

and

+s%2B+42+=+42+%2B+42+

+s+%2B+42+=+84+

------------------

The 1st train's speed is 42 mi/hr

The 2nd train's speed is 84 mi/hr

---------------------------

check:

(2) +d+=+%28+s%2B42+%29%2A2+

(2) +d+=84%2A2+

(2) +d+=+168+

and

(1) +d+-+2s+=+s%2A2+

(1) +d+-+2%2A42+=+42%2A2+

(1) +d+=+84+%2B+84+

(1) +d+=+168+

8 0

3 years ago