Well it depends...... (.5= 1/2)
For a probability distribution to be represented, it is needed that P(X = 0) + P(X = 1) = 0.44. Hence one possible example is:
<h3>What is needed for a discrete random variable to represent a probability distribution?</h3>
The sum of all the probabilities must be of 1, hence:
P(X = 0) + P(X = 1) + P(X = 3) + P(X = 4) + P(X = 5) = 1.
Then, considering the table:
P(X = 0) + P(X = 1) + 0.15 + 0.17 + 0.24 = 1
P(X = 0) + P(X = 1) + 0.56 = 1
P(X = 0) + P(X = 1) = 0.44.
Hence one possible example is:
More can be learned about probability distributions at brainly.com/question/24802582
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The answer is B. centroid, which is the intersection of three medians of the triangle's sides.
Let's look into other answers as well:
A. Circumcenter
It is the point where three perpendicular bisector meet, and is not correct as we can see there is no indication of right angles.
The first photo is what a circumcenter looks like:
C. Incenter
It is the point where the angle bisectors of the triangles meet, which is not indicated in the photo as well.
The second photo is what a incenter looks like:
D. Orthocenter
It is a point where the altitudes of a triangle intersect, and is not indicated by the figure.
The second photo is what a Orthocenter looks like:
Therefore the answer is B. Centroid.
Hope it helps!
Answer:
Sale price:$29.02
Step-by-step explanation:
32.5/100=0.325x43.00=13.975/13.98(rounded)
43.00-13.98=29.02
The mid-point of FJ is the number right in the middle of FJ. Find the mean of F & J. Add regardless of sign
4 + 6 = 10
10/2 = 5
Add 5 to -4
5 + -4 = 1
H is your midpoint
True. As long as AB and BC are on the same line, AB + BC = AC
hope this helps
