Answer:
Speed of hikers are 4.4 mph and 7.7 mph
Step-by-step explanation:
Two hikers are 55 miles apart and walking towards each other.
They meet after 10 hours.
Let the speeds of hikers are S and S' mph.
One hiker walks 3.3 mph faster than the other,
S = 3.3 + S'
S' = S - 3.3
Distance traveled by the hiker with higher speed S = Speed × Time
Distance traveled by the slower hiker 
= (S - 3.3) × 10
Total distance between them = 55 miles
10S + 10(S - 3.3) = 55
20S - 33 = 55
20S = 88
S = 4.4 mph
Speed of first hiker = 4.4 mph
Speed of second hiker = 4.4 + 3.3 = 7.7 mph
Exclusive events, for OR we can add probabilities.
P(O or B) = 0.49 + 0.20 = 0.69
Answer 0.69
Answer:
Step 1: y - 1
Step 2: x - 4
Step 3: (x-4)^2+(y-1)^2=3^2
There are 60 seconds in a minute, so divide 450 by 6 and you get that his first mile was in 75 minutes.
Answer:
The speed of Kali is 30 mph.
Step-by-step explanation:
Let, the speed of Kali be "x", then speed of Ndiba will be:
Speed of Ndiba = x + 15 mph
If, the time for travel for Ndiba is 2 hrs, when he catches Kali, and he left 1 hour later than Kali, then then time traveled by Kali at that instant will be 2+1 = 3hrs.
At the point of meeting both will have covered same distance.
Distance Covered by Kali = Distance Covered by Ndiba
(Speed of Kali)(Time traveled by Kali) = (Speed of Ndiba)(Time traveled by Ndiba)
(x)(3) = (x +15)(2)
3x = 2x +30
<u>x = 30 mph</u>
The correct answer is, actually 30 mph, by the solution shown above.
