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slamgirl [31]
2 years ago
14

If a shape has four sides, then it is a quadrilateral. A square has four sides. (It is asking What is a logical conclusion from

the given statements)
A. Therefor, a square is a polygon
B. Therefor, a square is a quadrilateral
C. Therefor, a square has four sides
D. Therefor, a square is a parallelogram
Mathematics
1 answer:
IRISSAK [1]2 years ago
6 0

Answer:

B: A square is a quadrilateral

Step-by-step explanation:

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What is 5,782 rounded to the nearest thousand​
olasank [31]

Answer:

6,000

Step-by-step explanation:

because it is a less amount of numbers to get to 6,000 than to get to 5,00

4 0
3 years ago
Read 2 more answers
Shirley has to travel 1600 meters to get to school. How many dekameters does she have to travel?
Mekhanik [1.2K]
Shirley has to travel 160 dekameters. 
4 0
3 years ago
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2. If the 4th term is 8 and the common difference is - 4, what are the first 3 terms of the arithmetic sequence? A. -4,0,4,8 B.
devlian [24]

Step-by-step explanation:

oi1i1iiiii1i1¹111111¹1o1ooooooo

3 0
3 years ago
A long distance runner starts at the beginning of a trail and runs at a rate of 4 miles per hour. two hours later, a cyclist sta
valina [46]

To solve this problem, let us first assign variables. Let us say that:

A = runner

B = cyclist

d = distance

v = velocity

time = t

 

The time in which the cyclist overtakes the runner is the time wherein the distance of the two is the same, that is:

dA = dB

 

We know that the formula for calculating distance is:

d = v t

therefore,

vA tA = vB tB

 

Further, we know that tA = tB + 2, therefore:

vA (tB + 2) = vB tB

4 (tB + 2) = 14 tB

4 tB + 8 = 14 tB

10 tB = 8

tB = 0.8 hours = 48 min

 

Therefore the cyclist overtakes the runner after 0.8 hours or 48 minutes.

8 0
3 years ago
a plane flying with the wind travels 630 mi in 1.5hrs. Flying against the wind , the plane travels 1120 mi in 4hrs. Find the rat
Flauer [41]
\bf \begin{cases}
r=\textit{rate of the plane}\\
w=\textit{rate of the wind}\\
\end{cases}
\\\\

\begin{array}{ccccllll}
&distance&rate&time(hrs)\\
&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\
\textit{with wind}&630&r+w&1\frac{1}{2}\\
\textit{against wind}&1120&r-w&4
\end{array}


\bf thus  \begin{cases}
630=(r+w)1\frac{1}{2}\to 630=(r+w)\frac{3}{2}
\\\\
1120=(r-w)4\\
--------------\\
630=(r+w)\frac{3}{2}\implies 630\cdot \frac{2}{3}=r+w\\
420=r+w\implies \boxed{420-w}=r\\
--------------\\
thus\\
--------------\\
1120=(r-w)4\implies 1120=4r-4w
\\\\
1120=4(\boxed{420-w})-4w
\end{cases}


solve for "w", to find the wind's speed rate,

so hmmm what's the plane's rate?  well 420 - w = r  :)
5 0
3 years ago
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