Answer:
Jerome got 5 quarters, 1 dime and, and 3 nickels.
Step-by-step explanation:
Let's define the variables:
N = number of nickels he got
D = number of dimes he got
Q = number of quarters he got
We know that the nickels were worth $0.15
And each nickel is whort $0.05
Then:
N*$0.05 = $0.15
N = $0.15/$0.05 = 3
N = 3
Now we also know that there is a total of 9 coins, then:
N + D + Q = 9
3 + D + Q = 9
D + Q = 9 - 3 = 6
D + Q = 6
And we also know that the total change received is $1.50, then:
D*$0.10 + Q*$0.25 + N*$0.05 = $1.50
We know that N = 3, then we can replace that and get:
D*$0.10 + Q*$0.25 + 3*$0.05 = $1.50
D*$0.10 + Q*$0.25 = $1.50 - $0.15 = $1.35
D*$0.10 + Q*$0.25 = $1.35
Then we have two equations:
D + Q = 6
D*$0.10 + Q*$0.25 = $1.35
To solve this, we can isolate one of the variables in one of the equations, i will isolate D in the first one:
D = 6 - Q
Now we can replace this in the other equation:
(6 - Q)*$0.10 + Q*$0.25 = $1.35
Now we need to solve this for Q.
$0.60 - Q*$0.10 + Q*$0.25 = $1.35
Q*$0.15 = $1.35 - $0.60 = $0.75
Q = ($0.75)/($0.15) = 5
Q = 5
Then Jerome has 5 quarters.
Now we can return to the equation:
N + Q + D = 9
We already know that:
N = 3
Q = 5
Then if we replace those in the equation, we get:
3 + 5 + D = 9
8 + D = 9
D = 9 - 8 = 1
D = 1
